Question

A rocket ship starts from rest and turns on its forward booster rockets, causing it to have a constant acceleration of 4 \,\dfrac{\text m}{{\text s}^2}4 s 2 m ? rightward. After 3\,\text s3s, what will be the velocity of the rocket ship? Answer using a coordinate system where rightward is positive.

Answer 1

Answer:

+12 m/s

Explanation:

The velocity of an object moving of accelerated motion is given by:

$v(t) = v_0 +at$

where

v0 is the initial velocity of the object

a is the acceleration

t is the time

In this problem, the rocket starts from rest, so $v_0 =0$. The acceleration is $a=4 m/s^2$, so the velocity after $t=3 s$ will be

$v(3 s)=0 +(4 m/s^2)(3 s)=+12 m/s$