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Pavel [41]
3 years ago
15

A rocket ship starts from rest and turns on its forward booster rockets, causing it to have a constant acceleration of 4 \,\dfra

c{\text m}{{\text s}^2}4 s 2 m ? rightward. After 3\,\text s3s, what will be the velocity of the rocket ship? Answer using a coordinate system where rightward is positive.
Physics
1 answer:
Sergio039 [100]3 years ago
6 0

Answer:

+12 m/s

Explanation:

The velocity of an object moving of accelerated motion is given by:

v(t) = v_0 +at

where

v0 is the initial velocity of the object

a is the acceleration

t is the time

In this problem, the rocket starts from rest, so v_0 =0. The acceleration is a=4 m/s^2, so the velocity after t=3 s will be

v(3 s)=0 +(4 m/s^2)(3 s)=+12 m/s

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