What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha
t the collision cross-section for the molecules of that gas is 2.0 � 10-20 m2? The Boltzmann constant is 1.38 � 10-23J/K, Avogadro's number is 6.02 � 1023 molecules/mole, and the ideal gas constant is R = 8.314 J/mol � K = 0.0821 L � atm/mol � K.
1 answer:
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A) The resultant force is 30.4 N at
B) The resultant force is 18.7 N at
Explanation:
A)
In order to find the resultant of the two forces, we must resolve each force along the x- and y- direction, and then add the components along each direction to find the components of the resultant.
The two forces are:
at
above x-axis
at
above y-axis
Resolving each force:
So, the components of the resultant are:
And the magnitude of the resultant is:
And the direction is:
B)
In this case, the 15 N is applied in the opposite direction to the 20 N force. Therefore we need to re-calculate its components, keeping in mind that the angle of the 15 N force this time is
So we have:
So, the components of the resultant this time are:
And the magnitude is:
And the direction is:
Learn more about vector addition:
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