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Assoli18 [71]
3 years ago
15

What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha

t the collision cross-section for the molecules of that gas is 2.0 � 10-20 m2? The Boltzmann constant is 1.38 � 10-23J/K, Avogadro's number is 6.02 � 1023 molecules/mole, and the ideal gas constant is R = 8.314 J/mol � K = 0.0821 L � atm/mol � K.

Physics
1 answer:
larisa86 [58]3 years ago
7 0

Explanation:

Below is an attachment containing the solution.

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Monochromatic light of wavelength λ=136.8μ m is shone at normal incidence through a thin film of thickness t resting atop a full
inn [45]

Answer:

1.8 × 10⁻⁸ Hm

Explanation:

Given that:

The refractive index of the film = 19

The wavelength of the light = 136.8 μ m

The thickness can be calculated by using the formula shown below as:

Thickness=\frac {\lambda}{4\times n}

Where, n is the refractive index of the film

{\lambda} is the wavelength

So, thickness is:

Thickness=\frac {136.8\ \mu\ m}{4\times 19}

Thickness = 1.8 μ m

Since,

1 μ m = 10⁻⁸ Hm

So,

Thickness = 1.8 × 10⁻⁸ Hm

7 0
2 years ago
An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see
siniylev [52]

Answer:

3.88 * 10^(-15) J

Explanation:

We know that the Potential energy of the electron at the beginning of its motion is equal to the Kinetic energy at the end of its motion, when it reaches the plates.

First, we get the potential and potential energy:

Electric potential = E * r

E = electric field

r = distance between plates

Potential = 2.2 * 10^6 * 0.011

= 2.42 * 10^4 V

The relationship between electric potential and potential energy is:

P. E. = q*V

q = charge of electron = 1.602 * 10^(-19) C

P. E. = 2.42 * 10^4 * 1.602 * 10^(-19)

P. E. = 3.88 * 10^(-15) J

6 0
2 years ago
A water tank holds water to the depth of the 80cm what is the pressure of the water of the tank​
Mashutka [201]

Answer:

7976 Pascals significant figure= 7.9*10^3

Explanation:

formula of hpg = height*density*gravitational energy

.80*10*997=7976 pascals

8 0
2 years ago
A shopper does 157 J of work pushing a cart with 10.9 N force
Tanzania [10]

The cart travelled a distance of 14.4 m

Explanation:

The work done by a force when pushing an object is given by:

W=Fd cos \theta

where:

F is the magnitude of the force

d is the displacement

\theta is the angle between the direction of the force and the displacement

In this problem we have:

W = 157 J is the work done on the cart

F = 10.9 N is the magnitude of the force

\theta=0^{\circ}, assuming the force is applied parallel to the motion of the cart

Therefore we can solve for d to find the distance travelled by the cart:

d=\frac{W}{F cos \theta}=\frac{157}{(10.9)(cos 0)}=14.4 m

Learn more about work:

brainly.com/question/6763771  

brainly.com/question/6443626  

#LearnwithBrainly

4 0
2 years ago
If a boy with 50kg run in 3m/s what is his velocity
stepladder [879]

His velocity is 3 m/s in the direction in which he is running in. which.

6 0
3 years ago
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