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3 years ago

Samples of different materials, A and B, have the same mass, but the sample

Physics

1 answer:

Effectus [21]3 years ago

3 0

Answer:

B. The particles that make up material B have more mass than the

particles that make up material A.

Explanation:

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What conditions must be met in order for work to be done?

Mashcka [7]

Answer:

i think the answer is D

Explanation:

srry if im wrong

4 0

2 years ago

A ball with a mass of 170 g which contains 3.80×108 excess electrons is dropped into a vertical shaft with a height of 145 m . A

yaroslaw [1]

Answer:

A. F=6.65*10^{-10}N

B. south - north

Explanation:

A) We use the Lorentz force

F = qv X B

|F| = qvB

to calculate the magnitude of the force we need the speed of the of the ball.

$v_{f}^{2}=v_{0}^{2}+2gy\\v_{f}=\sqrt{0+2(9.8\frac{m}{s^{2}})(145m)}=53.31\frac{m}{s}$

and by replacing in the formula for the magnitude of the force we have (taking into account the excess of electrons)

$F=(3.8*10^{8})(1.602*10^{-19}C)(53.31\frac{m}{s})(0.205T)=6.65*10^{-10}N$

b. south - north (by the rigth hand rule)

I hope this is usefull for you

regards

8 0

3 years ago

A car is moving at 19 m/s along a curve on a horizontal plane with radius of curvature 49m.

JulsSmile [24]

Answer:

$\mu =0.75$

Explanation:

<u>Frictional Force </u>

When the car is moving along the curve, it receives a force that tries to take it from the road. It's called centripetal force and the formula to compute it is:

$F_c=m.a_c$

The centripetal acceleration a_c is computed as

$\displaystyle a_c=\frac{v^2}{r}$

Where v is the tangent speed of the car and r is the radius of curvature. Replacing the formula into the first one

$F_c=m.\frac{v^2}{r}$

For the car to keep on the track, the friction must have the exact same value of the centripetal force and balance the forces. The friction force is computed as

$F_r=\mu N$

The normal force N is equal to the weight of the car, thus

$F_r=\mu .m.g$

Equating both forces

$\displaystyle \mu .m.g=m.\frac{v^2}{r}$

Simplifying

$\displaystyle \mu =\frac{v^2}{rg}$

Substituting the values

$\displaystyle \mu =\frac{19^2}{(49)(9.8)}$

$\boxed{\mu =0.75}$

7 0

3 years ago

I need to show my work as well but on the computer so, please show work for how you got the answers. Thank you!

balandron [24]

Answer:

1) $1H_2 + 1Cl_2$ => 2HCl

2) $2Al + 6HCl$ => $2AlCl_3 + 3H_2$

3) $1Ca_2Br_2 + 2NaCO_3$ => $2CaCO_3 + 2NaBr$

4) $3NaOH + 1FeCl_3$ => $3NaCl + 1Fe(OH)_3$

Explanation:

4 0

3 years ago

NemiM [27]

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Work is the force on the object as it changes a distance. Interestingly, as work is done on an object, potential energy can be stored in that object. For example, if you carry a load up the stairs. Now that load will have potential energy that can be transformed into kinetic energy and so on

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3 years ago