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weeeeeb [17]
3 years ago
12

Samples of different materials, A and B, have the same mass, but the sample

Physics
1 answer:
Effectus [21]3 years ago
3 0

Answer:

B. The particles that make up material B have more mass than the

particles that make up material A.

Explanation:

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Sand dunes during the Dust Bowl are an example of:
choli [55]

Sand dunes during the Dust Bowl are an example of windward.

The sand dunes are formed due to high movement of wind in the deserts which make dunes in the direction where wind is moving. Windward refers to facing the wind or situated on the side facing the wind so in those regions where the wind moves bring sand with itself and make dunes in that area so we can conclude that sand dunes are formed in the windward regions.

Learn more: brainly.com/question/24879138

5 0
3 years ago
The attractive electrostatic force between the point charges +8.44 ✕ 10-6 and q has a magnitude of 0.961 n when the separation b
d1i1m1o1n [39]
The electrostatic force between two charges Q1 and q is given by
F=k_e  \frac{Q_1 q}{r^2}
where 
ke is the Coulomb's constant
Q1 is the first charge
q is the second charge
r is the distance between the two charges

Re-arranging the formula, we have
q= \frac{F r^2}{k_e Q_1}
and since we know the value of the force F, of the charge Q1 and the distance r between the two charges, we can calculate the value of q:
q= \frac{(0.961 N)(0.67 m)^2}{(8.99 \cdot 10^9 N m^2 C^{-2})(+8.44\cdot 10^{-6}C)}=5.69 \cdot 10^{-6} C

And since the force is attractive, the two charges must have opposite sign, so the charge q must have negative sign.
6 0
3 years ago
Consider another special case in which the inclined plane is vertical (θ=π/2). In this case, for what value of m1 would the acce
Lana71 [14]

Answer:

Explanation:

Consider another special case in which the inclined plane is vertical (θ=π/2). In this case, for what value of m1 would the acceleration of the two blocks be equal to zero

F - Force

T = Tension

m = mass

a = acceleration

g = gravitational force

Let the  given Normal on block 2 = N

and N = m_2 g \cos \theta

and the tension in the given string is said to be T = m_2 g \sin \theta

When the acceleration a=\frac{F}{m_1}

for the said block 1.

It will definite be zero only when Force is zero , F=0.

Here by Force, F

I refer net force on block 1.

Now we know

F = m_1g-T.

It is known that if the said

\theta=\frac{\pi}{2} ,

then Tension T= m_2g [since \sin(\pi/2) = 1],

Now making "F = m_1g - m_2g"

So If we are to make Force equal to zero

F=0 => m_1g = m_2g \ or \ m_1 = m_2

6 0
3 years ago
A 21.6−g sample of an alloy at 93.00°C is placed into 50.0 g of water at 22.00°C in an insulated coffee-cup calorimeter with a h
IrinaK [193]

Answer : The specific heat capacity of the alloy 1.422J/g^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

C_1 = specific heat of alloy = ?

C_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of alloy = 21.6 g

m_2 = mass of water = 50.0 g

T_f = final temperature of system = 31.10^oC

T_1 = initial temperature of alloy = 93.00^oC

T_2 = initial temperature of water = 22.00^oC

Now put all the given values in the above formula, we get

21.6g\times c_1\times (31.10-93.00)^oC=-50.0g\times 4.18J/g^oC\times (31.10-22.00)^oC

c_1=1.422J/g^oC

Therefore, the specific heat capacity of the alloy 1.422J/g^oC

6 0
3 years ago
An elephant kicks a 2.5 kg rock that is initially at rest. The
erma4kov [3.2K]

0.20Answer:

Explanation:

6 0
3 years ago
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