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3 years ago

Which of the following is an example of Newton’s second law of motion?

Physics

2 answers:

inysia [295]3 years ago

5 0

Answer:

Explanation:

Newton’s Second Law of Motion

Newton’s Second Law of Motion states that ‘when an object is acted on by an outside force, the mass of the object equals the strength of the force times the resulting acceleration’.

This can be demonstrated dropping a rock or and tissue at the same time from a ladder. They fall at an equal rate—their acceleration is constant due to the force of gravity acting on them.

The rock's impact will be a much greater force when it hits the ground, because of its greater mass. If you drop the two objects into a dish of water, you can see how different the force of impact for each object was, based on the splash made in the water by each one.

Arada [10]3 years ago

4 0

Answer:

g ask ur teacher

Explanation:

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Velocity has two pieces of information.what are they

seraphim [82]

They are speed and direction.

3 0

4 years ago

A dart is thrown from 1.50 m high at 10.0 m/s toward a target 1.73 m from the ground. At what angle was the dart thrown?

Triss [41]

Answer:

The angle of projection is 12.26⁰.

Explanation:

Given;

initial position of the dart, h₀ = 1.50 m

height above the ground reached by the dart, h₁ = 1.73 m

maximum height reached by the dart, Hm = h₁ - h₀ = 1.73 m - 1.50 m= 0.23 m

velocity of the dart, u = 10 m/s

The maximum height reached by the projectile is calculated as;

$H_m = \frac{u^2sin^2 \theta}{2g}$

where;

θ is angle of projection

g is acceleration due to gravity = 9.8 m/s²

$H_m = \frac{u^2sin^2 \theta}{2g}\\\\sin^2 \theta = \frac{H_m \ \times \ 2g}{u^2} \\\\sin^2 \theta = \frac{0.23 \ \times \ 2(9.8)}{10^2} \\\\sin ^2\theta =0.04508\\\\sin \theta = \sqrt{0.04508} \\\\sin \theta = 0.2123\\\\\theta = sin^{-1}(0.2123)\\\\\theta = 12.26^0$

Therefore, the angle of projection is 12.26⁰.

6 0

3 years ago

A submersible pump is put under the water at the bottom of a well and is used to push water up through a pipe. What minimum outp

Fantom [35]

Answer:

The Required pressure for this situation is P= 735000Pa

Explanation:

In Determining the required pressure in this situation we use two equations

First one is

F = mg = (ρhA)g

And Second one is

P = $F/A$ = (ρhAg)/A Where P is pressure

We get

P = ρhg

since g = 9.8 m/s and h is given that is 75m and ρ = $1000 kg/m^3$

P = (9.8 m/s)( $1000 kg/m^3$ )(75) we get

P = 735000 Pa

6 0

4 years ago

Work done by a force forum X to X

Ksivusya [100]

Answer:

W = 68 J

Explanation:

On a force vs displacement chart, work is the area under the curve.

The area under the curve can be divided into a rectangle and a triangle

W = Fd = (2 N)(12 - 0 m) + ½(13 - 2 N)(12 - 4 m) = 68 N•m = J

5 0

3 years ago

A trash can slides on a level floor after being pushed by an unhappy student. It slows and comes to a stop with a constant accel

castortr0y [4]

Answer:

Explanation:

Given:

Acceleration, a = -2.4 m/s^2

Acceleration due to gravity, g = 9.8 m/s^2

Sum of forces = 0

Fr + F = 0

Fr = µsl × m × g

Since, Fn = m × g

m × a = (- µsl × mg)

µsl = -a/g

= 2.4/9.8

= 0.245

5 0

3 years ago