MG(S)+H2SO4(AQ)=MG2SO4(AQ) + H2(G)
0.24J/g*degC * 4.37g * 2.5degC = 2.622J
The 2.5 degC is the difference between 25 and 27.5 deg C.
The correct name is 3-methylhexane.
<h3>Structures : </h3>
The structure of 4-methylhexane is
CH3
|
CH3-CH2-CH2-CH-CH2-CH3
In the systematic nomenclature, the longest carbon chain is numbered so as to give the lowest number to the substituent.
CH3
|
CH3-CH2-CH2-CH-CH2-CH3
6 5 4 3 2 1
Hence the correct name is 3-methylhexane.
What is 3-methylhexane?
A branching hydrocarbon having two enantiomers is 3-methylhexane. It is one of heptane's isomers. The chirality of the molecule makes it one of only two structural isomers of heptane with this feature, the other being 2,3-dimethylpentane. 3-methylhexane and 3-methylhexane are the enantiomers.
<h3>Rules for naming the compound ? </h3>
- Typically, a molecular molecule consists of two or more nonmetal components.
- Molecular compounds are termed by using the stem of the first element's name plus the suffix -ide, followed by the second element. The number of atoms in a molecule is specified using numerical prefixes.
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Answer:
9Be
4
Explanation:
Atomic number = (3+2)-1= 4
Mass number = (6+4)-1 =9
Answer:
b. + 1.01 V
Explanation:
Sn(s) ⇒ Sn2+ + 2e⁻ Eox = 0.14 V
Ag₊ + e⁻⇒ Ered = 0.80 V
_______________________________
Sn(s) + Ag⁺(aq) ⇒ Sn2⁺(aq) + Ag(s) Eºcell = 0.14 V + 0.80 V = 0.94 V
This problem is solved by using the Nernst equation:
Ecell = Eºcell - (0.0592 / n) log Q
since we are not at standard condition given that the concentrations are not at 1 M. So we will calculate Q first
Q = ( Sn²⁺ ) / ( Ag⁺) = 0.022/2.7 = 0.0081
Ecell = 0.94 V -(0.0592/2) x log (0.0081) = 1.00 V