Answer:
sEE BELOW
Explanation:
Well.....because the numbers are 'astronomical'....meaning VERY, VERY , VERY LARGE
Answer:
b. able to travel through a vacuum.
Explanation:
The most distinguishing factor of an electromagnetic waves is that they are able to travel through a vacuum.
These waves do not require materials in a medium for propagation.
- Electromagnetic waves are formed by the propagation of the electric and magnetic fields.
- They vibrate at an angle of 90° .
- They are unlike like mechanical waves that requires that requires materials in medium for their propagation.
A covalent bond is considered covalent
Answer:
ΔK.E = 14 nJ
Explanation:
Solution:
- The charge that moves under the influence of an Electric Field produced between a potential difference (V) stores electric potential energy U within that is converted to kinetic energy.
- We will use conservation of energy on the system that contains the charged particle with charge q loses its electric potential energy U as it moves towards positively charged object that converts into a gain in Kinetic energy of the charged particle ΔK.E:
ΔK.E = U
Where,
U = V*q
ΔK.E = V*q
ΔK.E = (7*10^-6)*(2*10^-3)
ΔK.E = 14 nJ
- The gain in kinetic energy is 14 nJ.
Answer:
0.3405V
Explanation:
#Given a magnetic field of
, diameter= 18.5cm(r=9.25cm or 0.0925m), we find the magnetic flux of the loop as:
![\phi=B.(\pi r^2)cos 0\textdegree\\=1.9\pi\times 0.0925^2 \times cos 0\textdegree\\=5.107\times10^-^2 \ Tm^2](https://tex.z-dn.net/?f=%5Cphi%3DB.%28%5Cpi%20r%5E2%29cos%200%5Ctextdegree%5C%5C%3D1.9%5Cpi%5Ctimes%200.0925%5E2%20%5Ctimes%20cos%200%5Ctextdegree%5C%5C%3D5.107%5Ctimes10%5E-%5E2%20%5C%20Tm%5E2)
we can now calculate the induced emf,
:
![\frac{\phi}{\bigtriangleup t}=\frac{5.107\times 10^-^2}{0.15}\\=3.405\times 10^-^1V](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cphi%7D%7B%5Cbigtriangleup%20t%7D%3D%5Cfrac%7B5.107%5Ctimes%2010%5E-%5E2%7D%7B0.15%7D%5C%5C%3D3.405%5Ctimes%2010%5E-%5E1V)
Hence, the induced emf of the loop is 0.3405V