The response to whether the statements made by both technicians are correct is that;
D: Neither Technician A nor Technician B are correct.
<h3>Radio Antennas</h3>
In radios, antennas are the means by which signals to the sought frequency be it AM or FM are received.
Now, if the antenna is bad, it means it cannot pick any radio frequency at all and so Technician A is wrong.
Now, most commercial antennas usually come around a resistance of 60 ohms and so it is not required for a good antenna to have as much as 500 ohms resistance and so Technician B is wrong.
Read more about Antennas at; brainly.com/question/25789224
Answer:
The resistance is 24.9 Ω
Explanation:
The resistivity is equal to:
The area is:
A = 60 * 60 = 3600 um² = 0.36x10⁻⁴cm²
If NA is greater, then, the term 1/NA can be neglected, thus the equation:
Where
V = 0.44 V
E = 11.68*8.85x10¹⁴ f/cm
The length is:
L = 10 - 0.335 = 9.665 um
The resistance is:
Answer:
import java.util.*;
public class Main {
public static void main(String[] args) {
double milesPerGallon = 0;
int totalMiles = 0;
int totalGallons = 0;
double totalMPG = 0;
Scanner input = new Scanner(System.in);
while(true){
System.out.print("Enter the miles driven: ");
int miles = input.nextInt();
if(miles <= 0)
break;
else{
System.out.print("Enter the gallons used: ");
int gallons = input.nextInt();
totalMiles += miles;
totalGallons += gallons;
milesPerGallon = (double) miles/gallons;
totalMPG = (double) totalMiles / totalGallons;
System.out.printf("Miles per gallon for this trip is: %.1f\n", milesPerGallon);
System.out.printf("Total miles per gallon is: %.1f\n", totalMPG);
}
}
}
}
Explanation:
Initialize the variables
Create a while loop that iterates until the specified condition is met inside the loop
Inside the loop, ask the user to enter the miles. If the miles is less than or equal to 0, stop the loop. Otherwise, for each trip do the following: Ask the user to enter the gallons. Add the miles and gallons to totalMiles and totalGallons respectively. Calculate the milesPerGallon (divide miles by gallons). Calculate the totalMPG (divide totalMiles by totalGallons). Print the miles per gallon and total miles per gallon.
Answer:
the rate of heat loss by convection across the air space = 82.53 W
Explanation:
The film temperature
to kelvin = (5 + 273)K = 278 K
From the " thermophysical properties of gases at atmospheric pressure" table; At 
= 278 K ; by interpolation; we have the following
→ v 13.93 (10⁻⁶) m²/s
→ k = 0.0245 W/m.K
→ ∝ = 19.6(10⁻⁶)m²/s
→ Pr = 0.713
The Rayleigh number for vertical cavity
= 
= 
For the rectangular cavity enclosure , the Nusselt number empirical correlation:
h = 1.99 W/m².K
Finally; the rate of heat loss by convection across the air space;
q = hA(T₁ - T₂)
q = 1.99(1.4*0.96)(20-(-10))
q = 82.53 W
Answer:a detailed structured diagram or drawing.
Explanation:
