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2 years ago

Assume that a p+ - n diode is built with an n region width l smaller than a hole diffusion length (l

Engineering

1 answer:

RSB [31]2 years ago

7 0

Answer: hiiiiii

fff

Explanation:

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For a turning operation, you have selected a high-speed steel (HSS) tool and turning a hot rolled free machining steel. Your dep

Alisiya [41]

Answer:

MRR = 1.984

Explanation:

Given that

Depth of cut ,d=0.105 in

Diameter D= 1 in

Speed V= 105 sfpm

feed f= 0.015 ipr

Now the metal removal rate given as

MRR= 12 f V d

d= depth of cut

V= Speed

f=Feed

MRR= Metal removal rate

By putting the values

MRR= 12 f V d

MRR = 12 x 0.015 x 105 x 0.105

MRR = 1.984

Therefore answer is -

1.944

8 0

2 years ago

A strip ofmetal is originally 1.2m long. Itis stretched in three steps: first to a length of 1.6m, then to 2.2 m, and finally to

andreyandreev [35.5K]

Answer:

strains for the respective cases are

0.287

0.318

0.127

and for the entire process 0.733

Explanation:

The formula for the true strain is given as:

$\epsilon =\ln \frac{l}{l_{o}}$

Where

$\epsilon =$ True strain

l= length of the member after deformation

$l_{o} =$ original length of the member

Now for the first case we have

l= 1.6m

$l_{o} = 1.2m$

thus,

$\epsilon =\ln \frac{1.6}{1.2}$

$\epsilon =0.287$

similarly for the second case we have

l= 2.2m

$l_{o} = 1.6m$ (as the length is changing from 1.6m in this case)

thus,

$\epsilon =\ln \frac{2.2}{1.6}$

$\epsilon =0.318$

Now for the third case

l= 2.5m

$l_{o} = 2.2m$

thus,

$\epsilon =\ln \frac{2.5}{2.2}$

$\epsilon =0.127$

Now the true strain for the entire process

l=2.5m

$l_{o} = 1.2m$

thus,

$\epsilon =\ln \frac{2.5}{1.2}$

$\epsilon =0.733$

6 0

2 years ago

Alternating current flows in___ direction(s) and direct current flows in___direction(s)

Oduvanchick [21]

Answer:

both, one

Explanation:

Alternating current flows in both directions and direct current flows in one direction.

Hope it helps.

;)

<3

8 0

2 years ago

The contact angle between the mercury surface and capillary tube wall is______ A) Less than 90 B) Equal to 90 C) Greater than 90

MakcuM [25]

Answer:

The Answer to the question is :

Explanation:

The contact angle between the mercury surface and capillary tube wall is Greater than 90.

If the surface of the solid is hydrophobic, the contact angle will be greater than 90 °. On very hydrophobic surfaces the angle can be greater than 150º and even close to 180º.

8 0

2 years ago

A sealed, rigid vessel of 2 m3 contains a saturated mixture of liquid and vapor R-134a at 10C. If it is heated to 50 C, the liqu

Iteru [2.4K]

Answer: 93.30kg

Explanation:

in the attachment

8 0

3 years ago