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3 years ago

A 860 kΩ resistor has 34 μA of current. What is the supply voltage for this electric circuit?

Engineering

2 answers:

Juliette [100K]3 years ago

8 0

Explanation:

first changing kilo ohm to ohm

860000 = 860 kΩ

and change 34 micro ampare to ampare

34 μA=3.4×10^-5

recalling the equation V=I*R

V= 3.4×10^-5×860000

v=29.24

deff fn [24]3 years ago

6 0

Answer:

v=IR

V= 860 x 10^3 x 34 x 10^-6

V=29240 x 10^-3

V=29.24 V

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