Question

A 860 kΩ resistor has 34 μA of current. What is the supply voltage for this electric circuit?

Answer 1

Explanation:

first changing kilo ohm to ohm

860000 = 860 kΩ

and change 34 micro ampare to ampare

34 μA=3.4×10^-5

recalling the equation V=I*R

V= 3.4×10^-5×860000

v=29.24

Answer 2

Answer:

v=IR

V= 860 x 10^3 x 34 x 10^-6

V=29240 x 10^-3

V=29.24 V