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masha68 [24]
2 years ago
15

The velocity of a particle which moves along the s-axis is given by = 40 − 3 2/ , ℎ t is in seconds. Calculate the displacement

∆ of the particle during the interval from t = 2sec to 4sec.
Engineering
1 answer:
scoundrel [369]2 years ago
8 0

The displacement ∆S of the particle during the interval from t = 2sec to 4sec is; 210 sec

<h3>How to find the displacement?</h3>

We are given the velocity equation as;

s' = 40 - 3t²

Thus, the speed equation will be gotten by integration of the velocity equation to get;

s = ∫40 - 3t²

s = 40t - ¹/₂t³

Thus, the displacement between times of t = 2 sec and t = 4 sec is;

∆S = [40(4) - ¹/₂(4)³] - [40(2) - ¹/₂(2)³]

∆S = 210 m

Read more about Displacement at; brainly.com/question/4931057

#SPJ1

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Answer:

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4 0
2 years ago
An alloy has a yield strength of 818 MPa and an elastic modulus of 104 GPa. Calculate the modulus of resilience for this alloy [
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Answer:

Modulus of resilience will be 3216942.308j/m^3

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5 0
3 years ago
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Answer:

V = 125.7m/min

Explanation:

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To calculate the cutting speed, let's use the formula :

T = \frac{pi* D * L}{V*F}

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Substituting values we have:

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V = 125.68 m/min ≈ 125.7 m/min

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Answer:

See explaination

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