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goldfiish [28.3K]
3 years ago
12

Determine the required dimensions of a column with a square cross section to carry an axial compressive load of 6500 lb if its l

ength is 64 in and its ends are fixed. Use a design factor of 3.0. Use aluminum 6061-T6.
Engineering
2 answers:
Hoochie [10]3 years ago
5 0

Answer:

The dimensions are 0.95 in

Explanation:

Given:

l = length = 64 in

lc/2 = 64/2 = 32 in

FOS = factor of safety = 3

E = 10.6x10⁶ psi

σ = 40000 psi

The square section is

I = a⁴/12

P=\frac{\pi^{2}*E*I  }{lc^{2} }\\6500=\frac{\pi ^{2}*10.6x10^{6}*a^{4}   }{12*32^{2} } \\a=0.95in

σallowable = σ/3 = 40000/3 = 13333.3 psi

Area = a² = 0.95² = 0.902 in²

σactual = 6500/0.902 = 7206.2 psi

like σactual < σallowable, the dimensions are 0.95 in

ycow [4]3 years ago
3 0

Answer: 0.95 inches

Explanation:

A direct load on a column is considered or referred to as an axial compressive load. A direct concentric load is considered axial. If the load is off center it is termed eccentric and is no longer axially applied.

The length= 64 inches

Ends are fixed Le= 64/2 = 32 inches

Factor Of Safety (FOS) = 3. 0

E= 10.6× 10^6 ps

σy= 4000ps

The square cross-section= ia^4/12

PE= π^2EI/Le^2

6500= 3.142^2 × 10^6 × a^4/12×32^2

a^4= 0.81 => a=0.81 inches => a=0.95 inches

Given σy= 4000ps

σallowable= σy/3= 40000/3= 13333. 33psi

Load acting= 6500

Area= a^2= 0.95 ×0.95= 0.9025

σactual=6500/0.9025

σ actual < σallowable

The dimension a= 0.95 inches

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using namespace std;

//Function Declarations

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void add()

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  cout << "\nmatrix1 # of columns: ";

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      for(j=0;j<cols1;j++)

      {

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      for(j=0;j<cols2;j++)

      {

          cout << "\nEnter element (" << i << "," << j << "): ";

          cin >> m2[i][j];

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      }

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  cout << "\n";

  for(i=0;i<rows2;i++)

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      for(j=0;j<cols2;j++)

          cout << m2[i][j] << " ";

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      cout << "\n";

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  main();

 

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  int rows1,cols1,i,j,k,rows2,cols2;

  cout << "\nmatrix1 # of rows: ";

  cin >> rows1;

 

  cout << "\nmatrix1 # of columns: ";

  cin >> cols1;

 

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  cout << "\nmatrix1 # of rows: ";

  cin >> rows1;

 

  cout << "\nmatrix1 # of columns: ";

  cin >> cols1;

 

   int m1[rows1][cols1];

 

  for(i=0;i<rows1;i++)

      for(j=0;j<cols1;j++)

      {

          cout << "\nEnter element (" << i << "," << j << "): ";

          cin >> m1[i][j];

          cout << "\n";

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  cout << "\n";

  for(i=0;i<rows1;i++)

  {

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          cout << m1[i][j] << " ";

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  cout << "\nmatrix2 # of columns: ";

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      {

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