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Likurg_2 [28]
3 years ago
6

Determine whether the following statements describe chemical or physical properties: (a) Oxygen gas supports combustion. (b) Fer

tilizers help to increase agricultural production. (c) Water boils below 1000C on top of a mountain. (d) Lead is denser than aluminum. (e) Uranium is a radioactive element.
Chemistry
1 answer:
sdas [7]3 years ago
7 0

Explanation:

A change that does not cause any change in chemical composition of a substance is known as a physical change.

For example, mass, density, volume etc are all physical changes.

On the other hand, a change that brings change in chemical composition of a substance is known as chemical change.

For example, combustion, toxicity, reactivity etc are all chemical changes.

Hence, following statements are identified as chemical or physical changes as follows.

(a) Oxygen gas supports combustion : Chemical change

(b) Fertilizers help to increase agricultural production : Chemical change

(c) Water boils below 100^{o}C on top of a mountain : Physical change

(d) Lead is denser than aluminum : Physical change

(e) Uranium is a radioactive element : Chemical change

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An isotope has a half-life of 10 minutes. after 20 minutes, what percentage of the original nuclei remain?
Elena-2011 [213]
To solve this, we can use two equations.
t1/2 = ln 2 / λ = 0.693 / λ  
   
where, t1/2 is half-life and λ is the decay constant.

t1/2 = 10 min = 0.693 / λ

Hence, λ = 0.693 / 10 min              -         (1)

Nt = Nο e∧(-λt)    
                
Nt = amount of atoms at t =t time
Nο= initial amount of atoms
t = time taken

by rearranging the equation,
Nt/Nο = e∧(-λt)                  -  (2)

From (1) and (2),

Nt/Nο = e∧(-(0.693 / 10 min) x 20 min) 
Nt/Nο = 0.2500

Percentage of remaining nuclei = (nuclei at t time / initial nuclei) x 100%
                                                     
= (Nt/Nο ) x 100%
                                                      = 0.2500 x 100%
                                                      = 25.00%

Hence, Percentage of remaining nuclei is 25.00%
6 0
3 years ago
What pressure is required to compress 196.0 liters of air at 1.83 atmosphere into a cylinder whose volume is 26.0 liters
drek231 [11]

Answer:

P₂ = 13.79 atm

Explanation:

Given data:

Initial volume = 196.0 L

Initial pressure = 1.83 atm

Final volume = 26.0 L

Final pressure = ?

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.83 atm × 196.0 L = P₂× 26.0 L

P₂ = 358.68 atm. L /  26.0 L

P₂ = 13.79 atm  

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