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timurjin [86]
3 years ago
13

Which of the following best describes an empirical formula?

Chemistry
1 answer:
Monica [59]3 years ago
6 0

Answer:

Option C :

a chemical formula that shows the relative number of each type of atom in a molecule, using the smallest possible ratio

Explanation:

Empirical Formula:

Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.

So,

Tha ration of the molecular formula should be divided by whole number to get the simplest ratio of molecule

For Example

      C₂H₆O₂ Consist of  Carbon (C), Hydrogen (H), and Oxygen (O)

Now

Look at the ratio of these three atoms in the compound

                         C : H : O

                         2 : 6 : 2

Divide the ratio by two to get simplest ratio

                          C : H : O

                         2/2 : 6/2 : 2/2

                             1 : 3 : 1

So for the empirical formula the simplest ratio of carbon to hydrogen to oxygen is 1:3:1

So the empirical formula will be

                     Empirical formula of C₂H₆O₂ = CH₃O

So, Option C is correct :

a chemical formula that shows the relative number of each type of atom in a molecule, using the smallest possible ratio

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Answer:

Density = 8.92 \ g/mL

Explanation:

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The decomposition of dinitrogen pentaoxide has an activation energy of 102 kj/mol and \delta ? h°rxn = + 55 kj/mol. what is the
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For an endothermic reaction, the products will be closer in energy to the transition state than what the reactans will be; so, the activation energy of the reversed reaction is lower than the activation energy of the forward reaction.

Activation energy of reverse and forward reactions is related by:

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8 0
3 years ago
A chemist adds 1.80L of a 1.1/molL aluminum chloride AlCl3 solution to a reaction flask. Calculate the millimoles of aluminum ch
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Answer:

2000 millimoles of AlCl₃

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 1.8 L

Molarity of solution = 1.1 mol /L

Millmole of AlCl₃ =?

Next, we shall determine the number of mole of AlCl₃ in the solution.

This can be obtained as follow:

Volume of solution = 1.8 L

Molarity of AlCl₃ solution = 1.1 mol /L

Number of mole of AlCl₃ =?

Molarity = mole /Volume

1.1 = Number of mole of AlCl₃ / 1.8

Cross multiply

Number of mole of AlCl₃ = 1.1 × 1.8

Number of mole of AlCl₃ = 1.98 moles

Finally, we shall convert 1.98 moles to millimoles. This can be obtained as follow:

1 mole = 1000 millimoles

Therefore,

1.98 mole = 1.98 mole × 1000 millimoles / 1 mole

1.98 mole = 1980 millimoles

1.98 mole ≈ 2000 millimoles

Thus, the chemist added 2000 millimoles of AlCl₃

7 0
3 years ago
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