Answer:
Explanation:
To write the chemical symbol for an atom or cation with 22 electrons, we must understand some few things about an atom.
An atom is made up of positively charged paticles called protons which are located in the nucleus. The neutrons do not have any charges and are they reside together in the nucleus with the protons.
Electrons are negatively charged particles which orbits the nucleus.
Titanium in its neutral state is the 22nd element on the periodic table and it has 22 electrons.
Vanadium is the the 23rd element on the periodic table. If it loses an electron, it becomes positively charged and it is a cation.
Chromium is the 24th element on the periodic table. A loss of two electrons makes the net electrons remaining on it 22.
The symbols are:
₂₂Ti
₂₃V¹⁺
₂₄Cr²⁺
<span>Ksp = 1.2 x 10^-17 = [Zn2+] [OH-]^2
Zn(OH)2 <----> Zn2+ + 2OH-
[Zn2+] = x
[OH-] = 2x
1.2 x 10^-17 = (x) ( 2x)^2 = 4 x ^3
x = 1.4 x 10^-6 M
2x = 2.8 x 10^-6 M
pOH = - log 2.8 x 10^-6 = 5.5
pH = 14 - 5.5 =8.5
i think this is it
</span>
Are u talking about electron sublevel config or where the electrons show in the "rings" of the atom
Answer:
its is letter c is your answer
Explanation:
I hope this help
