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2 years ago

(a)0.444 Mol of COCl2 in 0.654 L of solution

1 answer:

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iron will react with oxygen to produce Fe2O3. how many grams of Fe2O3 will he produced if 0.18 mil of Fe reacts?

nasty-shy [4]

Answer:

14.4g

Explanation:

First, we need to write a balanced equation for the reaction between Fe and O2 to produce Fe2O3. This is illustrated below:

4Fe + 3O2 —> 2Fe2O3

From the balanced equation,

4moles of Fe produced 2moles of Fe2O3.

Therefore, 0.18mol of Fe will produce = (0.18x2) /4 = 0.09mol of Fe2O3.

Now we need to find the mass present in 0.09mol of Fe2O3. This can be achieved by doing the following:

Molar Mass of Fe2O3 = (56x2) + (16x3) = 112 + 48 = 160g/mol

Number of mole of Fe2O3 = 0.09mol

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass of Fe2O3 = 0.09 x 160 = 14.4g

6 0

2 years ago

When does carbon dioxide absorb the most heat energy

Artemon [7]

Answer:

in its final stage

Explanation:

8 0

3 years ago

Read 2 more answers

What is the definition of an integral membrane protein? a It is a protein that is found on the inside of the plasma membrane b I

Bezzdna [24]

An integral membrane protein is a type of membrane protein that is permanently attached to the biological membrane.

7 0

2 years ago

Barium fluoride (BaF2) has a Ksp = 2. 5 × 10–5 (mol/L)3.

vagabundo [1.1K]

This problem is asking for the dissolution reaction of barium fluoride, both the equilibrium and Ksp expressions in terms of concentrations and x and its molar solubility in water. Thus, answers shown below:

$BaF_2(s)\rightleftharpoons Ba^{2+}(aq)+2F^-(aq)$
$Ksp=[Ba^{2+}][F^-]^2$
$Ksp=(x)(2x)^2$
0.0184 M.

<h3>Solubility product</h3>

In chemistry, when a solid is dissolved in water, one must take into account the fact that not necessarily its 100 % will be able to break into ions and thus undergo dissolution.

In such a way, and specially for sparingly soluble solids, one ought to write the dissolution reaction at equilibrium as shown below for the given barium fluoride:

$BaF_2(s)\rightleftharpoons Ba^{2+}(aq)+2F^-(aq)$

Next, we can write its equilibrium expression according to the law of mass action, which also demands us to omit any solid and refer it to the solubility product constant (Ksp):

$Ksp=[Ba^{2+}][F^-]^2$

Afterwards, one can insert the reaction extent, x, as it stands for the molar solubility of this solid in water, taking into account the coefficients balancing the reaction:

$Ksp=(x)(2x)^2$

Finally, we solve for the x as the molar solubility of barium fluoride as shown below:

$2.5x10^{-5}=(x)(2x)^2\\\\2.5x10^{-5}=4x^3\\\\x=\sqrt[3]{\frac{2.5x10^{-5}}{4} } \\\\x=0.0184M$

Learn more about chemical equilibrium: brainly.com/question/26453983

6 0

2 years ago

Allen is carrying out reactions in a lab. One of the products in all reactions is found to be either a precipitate, a gas, or wa

krek1111 [17]

I think the best answer among the choices given is option A. The reactions are all decomposition reactions because decomposition reactions can produce either a precipitate, a gas and a water in a single reaction. However, these products can also be produced by other type of reactions.

8 0

3 years ago