Methane CH4 CH4 1 hexane C6H14 CH3(CH2)4CH3 5
ethane C2H6 CH3CH3 1 heptane C7H16 CH3(CH2)5CH3 9
propane C3H8 CH3CH2CH3 1 octane C8H18 CH3(CH2)6CH3 18
butane C4H10 CH3CH2CH2CH3 2 nonane C9H20 CH3(CH2)7CH3 35
pentane C5H12 CH3(CH2)3CH3 3 decane C10H22 CH3(CH2)8CH3 75
PE, GO, XY - I am probably wrong xoxoxoxoxxo
1.No eating in the lab
2.No running around in the lab
3.Wear gloves while performing experiments
4.Clen your hands before you leave the lab
Answer:
The rate would be lower and the concentration of reactants would be lower.
Explanation:
The rate of a chemical reaction depends on the rate constant and the concentration of reactants.
For Ex:
For a reaction experimentally given by A + B ----> C + D
Rate = k[A][B]
where k is the rate constant
[A] = concentration of reactant A
[B] = concentration of reactant B
As the reaction proceeds,the concentration of reactant decrease and concentration of products increase.Rate constant k depends only on temperature and activation energy.Hence it will remain constant throughout the reaction assuming that reaction is carried out at constant temperature and pressure.
Hence rate will depend only on concentration of reactants and hence decrease with decrease in concentration of reactants.
