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3 years ago

PLZ SOLVE ALL 10

Physics

1 answer:

lana [24]3 years ago

3 0

1) Carbohydrates, Lipids (fats), Protein, Vitamins, Minerals, and Water. proteins, fats and carbs provide energy.

2) 45 to 65 percent carbs, and 10-35 percent protein.

3) Carbs are your body's main source of energy. the 2 major types are simple and complex carbs

4) cereals, fruits and vegetables. You should have 25 to 30 grams a day.

5) It helps repair and build your body's tissues, allows metabolic reactions to take place and coordinates bodily functions.

6) It gives you energy and supports cell growth.

7) Saturated fats, Trans fats, Monounsaturated fats, and Polyunsaturated fats. trans fats are the most dangerous for your health

8) Vitamins and minerals are considered essential nutrients, They help shore up bones, heal wounds, and bolster your immune system. They can also help convert food into energy.

9) Minerals help build strong bones to transmitting nerve impulses. Some minerals are even used to make hormones or maintain a normal heartbeat.

10) 60% is made of water, 11 to 15 cups of water should be drank a day.

hope this helps :)

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4 years ago

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3 years ago

The force F required to compress a spring a distance x is given by F 2 F0 5 kx where k is the spring constant and F0 is the prel

IrinaVladis [17]

Answer:

a)W=8.333lbf.ft

b)W=0.0107 Btu.

Explanation:

<u>Complete question</u>

The force F required to compress a spring a distance x is given by F– F0 = kx where k is the spring constant and F0 is the preload. Determine the work required to compress a spring whose spring constant is k= 200 lbf/in a distance of one inch starting from its free length where F0 = 0 lbf. Express your answer in both lbf-ft and Btu.

Solution

Preload = F₀=0 lbf

Spring constant k= 200 lbf/in

Initial length of spring x₁=0

Final length of spring x₂= 1 in

At any point, the force during deflection of a spring is given by;

F= F₀× kx where F₀ initial force, k is spring constant and x is the deflection from original point of the spring.

$W=\int\limits^2_1 {} \, Fds \\\\\\W=\int\limits^2_1( {F_0+kx} \,) dx \\\\\\W=\int\limits^a_b {kx} \, dx ; F_0=0\\\\\\W=k\int\limits^2_1 {x} \, dx \\\\\\W=k*\frac{1}{2} (x_2^{2}-x_1^{2} )\\\\\\W=200*\frac{1}{2} (1^2-0)\\\\\\W=100.lbf.in\\\\$

Change to lbf.ft by dividing the value by 12 because 1ft=12 in

100/12 = 8.333 lbf.ft

work required to compress the spring, W=8.333lbf.ft

The work required to compress the spring in Btu will be;

1 Btu= 778 lbf.ft

?= 8.333 lbf.ft----------------cross multiply

(8.333*1)/ 778 =0.0107 Btu.

6 0

3 years ago