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chubhunter [2.5K]
3 years ago
15

Is a force that opposes the motion between two objects in contact with each other.

Physics
2 answers:
Sergeeva-Olga [200]3 years ago
7 0

Answer: Friction  :)        

Wewaii [24]3 years ago
6 0
The answer above is correct. It is friction!
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If distance between two charges increased 5 times then force between them
Marrrta [24]

decreased 5 times

Explanation: if the force increases 5 times between them would decrease 5 times

4 0
3 years ago
A football wide receiver rushes 16 m straight down the playing field in 2.9 s (in the positive direction). He is then hit and pu
Bumek [7]

Answer:

a) v1 = 5.52m/s

b) v2 = -1.52m/s

c) v3 = 4.62m/s

d) vt = 3.85m/s

Explanation:

The velocity of the football wide receiver is his displacement per unit time.

Velocity v = (displacement d)/time t

v = d/t .....1

For each of the cases, equation 1 would be used to calculate the velocity.

a) v1 = d1/t1

d1= 16m

t1 = 2.9s

v1 = 16m/2.9s

v1 = 5.52m/s

b) v2 = d2/t2

d2 = -2.5m

t2 = 1.65s

v2 = -2.5/1.65

v2 = -1.52m/s

c) v3 = d3/t3

d3 = 24m

t3 = 5.2s

v3 = 24/5.2

v3 = 4.62m/s

d) vt = dt/tt

dt = 16m - 2.5m + 24m = 37.5m

tt = 2.9 + 1.65 + 5.2 = 9.75s

vt = 37.5/9.75

vt = 3.85m/s

5 0
3 years ago
A pyrotechnical releases a 3 kg firecracker from rest. at t=0.4 s, the firecracker is moving downward with a speed 4 m/s. At the
olga2289 [7]

Answer:

a) F = 30 N, b)   I = 12 N s , c)  I = -12 N s , d) ΔI = 0 N s

Explanation:

This exercise is a case at the moment, let's define the system formed by the firecracker and its two parts, in this case the forces during the explosion are internal and the moment is conserved

Initial, before the explosion

     p₀ = m v

The speed can be found by kinematics

     v = v₀ - g t

     v = 0 - 10 0.4

     v = -4.0 m / s

Final after division

     pf = m₁ v₁f + m₂ v₂f

    p₀ = pf

    M v = m₁ v₁f + m₂ v₂f

Where M is the initial mass (M = 3 kg), m₁ is the mass mtop (m₁ = 1 kg) and m₂ in the mass m botton (m₂ = 2kg) and the piece that moves up (v₁f = 6m/s )

a) before the explosion the only force acting on the body is gravity

     F = mg

     F = 3 10 = 30 N

b) The expression for momentum is

     I = Ft

Before the explosion the only force that acts is the weight

    I = mg t

    I = 3 10 0.4

    I = 12 N s

c) To calculate this part we use the conservation of the moment and calculate the speed of the body that descends body 2

    M v = m₁ v₁f + m₂ v₂f

    v₂f = (M v - m₁ v₁f) / m₂

    v₂f = (3 (-4) - 1 6) / 2

   v₂f = - 9 m / 2

The negative sign indicates that body 2 (botton) is descending

Now we can use the momentum and momentum relationship for the body during the explosion

    I = F t = Dp

   F t = pf –po)

   F t= [m₁ v₁f + m₂ v₂f]

   

   I = [1 6 + 2 (-9) -0]

   I = -12 N s

This is the impulse during the explosion the negative sign indicates that it is headed down

d) impulse change

I₀ = Mv

I₀ = 3 *4

I₀ =-12 N s

 ΔI =If – I₀  

ΔI = - 12 – (-12)

ΔI = -0 N s

3 0
3 years ago
The results of a recent television survey of American TV households revealed that 86 out of every 100 TV households have at leas
Lelechka [254]

Answer:

q = \dfrac{14}{100}

Explanation:

given,

86 out of every 100 TV households have at least one remote control

Probability of any material is calculated by.

Probability = \dfrac{favourable\ outcome}{Total\ outcome}

P(at\ least\ one\ remote\ control)=\dfrac{86}{100}

P(at\ least\ one\ remote\ control)=0.86

now, Calculating probability that at least one remote control

   q = 1 - 0.86

   q = 0.14

P(doesnot\ have\ at\ least\ one\ remote\ control)=\dfrac{14}{100}

q = \dfrac{14}{100}

7 0
3 years ago
8. Il An 8.00 kg package in a mail-sorting room slides 2.00 m down a
Vitek1552 [10]

Answer:

See below

Explanation:

Normal force = m g cos 53 = 8 kg * 9.8 m/s^2 * cos 53 = 47.1823 N

  no work is done by this force

Force friction = coeff friction * force normal = .4 * 47.1823 = 7.55 N

   work of friction = 7.55 * 2 m = 15.1 j

Force Downplane = mg sin 53 = 62.61  N

    work = 62.61 * 2 = 125.22 j

Net Force downplane =   force downplane - force friction = 55.06 N

net Work = force * distance = 55.06 N * 2 M = 110.12 j

3 0
2 years ago
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