Answer:
Explanation:
System models are created and used in order for all of the individuals involved in the process to be able to see exactly how each module that is being created connects to the rest of the system. This allows every developer to understand each module's/part's function and develop it with the entire system in mind. This also makes it easier to implement newer features. If a model is not made then the developers may miss key features and when it is time to piece all of the components of the system together, the overall process can become a jumbled mess.
Answer:
I would say 10000;1 but thats just me
Explanation:
Answer:
water=14.1 kg
air=0.1348kg
Explanation:
Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)
through prior knowledge of two other properties such as pressure and temperature.
To solve this exercise we must find the specific volume of water and air in the two states and then subtract them and multiply them by the volume of the tank to find the change in mass, the following equation is inferred
Δm=V(ρ2-ρ1)
Where V= tank volume=500L=0.5m^3
ρ2= density of fluid in state 2
ρ1=density of fluid in state 1
Δm=change of mass
for water
ρ1=971.8kg/m^3(80C)
ρ2=1000kg/m^3(5C)
Δm=0.5(1000-971.8)
Δm=14.1 kg
for air
ρ1=0.9994kg/m^3(80C)
ρ2=1.269kg/m^3(5C)
Δm=0.5(1.269-0.9994)
Δm=0.1348kg
Answer:
the endurance strength = 421.24 MPa
Explanation:
hope this helps :-)
Answer:
provide 180 mm spacing
Explanation:
GIVEN DATA
rectangular beam: (b) = 300 mm, (d) = 575 mm
reinforced for flexure = 4Ф32 bars
WD = 30 kN /m, WL = 45 kN/m
Wu = 1.4 * 30 + 1.6 * 45 = 114 kN/m
i) concrete shear stress ( vc)
100 Ac / bd = (100 * u *
* 32^2) / 300 * 575 = 1.865
from table 3.8
when: 100 Ac / bd = 1.865 then Vc = 0.778 N/mm^2
Ultimate shear force = (114 *5.5) / 2 = 313.5 kN
design shear stress = V / bd = (313.5 * 10^3) / (300 * 575) = 1.82 N/mm^2
v < 0.8
= 1.82 < 3.75
design link provided according to
Asv / sv = b(v-vc) / 0.87 fy = 300(1.82 - 0.778) / 0.87 (420)
ASv / Sv = 0.855
From table 3.13 :the value of Asv / sv can be calculated as

x = (-25) [ 0.625] + 200 = 184.375 mm
provide 180 mm spacing