The energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.
<h3>Change in energy level of the electron</h3>
When photons jump from a higher energy level to a lower level, they emit or radiate energy.
The change in energy level of the electrons is calculated as follows;
ΔE = Eb - Ef
ΔE = -2.68 eV - (-5.74 eV)
ΔE = 3.06 eV
Thus, the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.
Learn more about energy level here: brainly.com/question/14287666
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The source and the observer are moving towards each other. The observer is moving toward the source. The source is moving away from the observer
Answer:
I think it has to do something with their ionizations... not entirely sure though.
Explanation:
Answer: 129.5 m
Explanation:
310 + 115 + 25 + 68 = 518
518 / 4 = 129.5 m
i think. Sorry if this is wrong
:)
