Answer:
75.36 mph
Explanation:
The distance between the other car and the intersection is,
The distance between the police car and the intersection is,
(Negative sign indicates that he is moving towards the intersection)
Therefore the distance between them is given by,
The rate of change is,
Now finding
when
from (1) we have
The officer's radar gun indicates 25 mph pointed at the other car then,
when
from
From (2) we get
Hence the speed of the car is 
Answer: chemical property
Explanation:
Complete Question
The complete question is shown on the first uploaded image
Answer:
The maximum emf is 
The emf induced at t = 1.00 s is 
The maximum rate of change of magnetic flux is 
Explanation:
From the question we are told that
The number of turns is N = 44 turns
The length of the coil is 
The width of the coil is 
The magnetic field is 
The angular speed is 
Generally the induced emf is mathematically represented as

Where
is the maximum induced emf and this is mathematically represented as

Where
is the magnetic flux
N is the number of turns
A is the area of the coil which is mathematically evaluated as

Substituting values


substituting values into the equation for maximum induced emf


given that the time t = 1.0sec
substituting values into the equation for induced emf 


The maximum induced emf can also be represented mathematically as

Where
is the magnetic flux and
is the maximum rate at which magnetic flux changes the value of the maximum rate of change of magnetic flux is

Answer:
scientists will use absolute dating to find how old a fossil exactly is.
Answer:
Explanation:
Given that a coil has a turns of
N = 110 turns
And the flux is given as function of t
ΦB = 9.75 ✕ 10^-3 sin(ωt),
Given that, at an instant the angular velocity is 8.70 ✕ 10² rev/min
ω = 8.70 ✕ 10² rev/min
Converting this to rad/sec
1 rev = 2πrad
Then,
ω = 8.7 × 10² × 2π / 60
ω = 91.11 rad/s
Now, we want to find the induced EMF as a function of time
EMF is given as
ε = —NdΦB/dt
ΦB = 9.75 ✕ 10^-3 sin(ωt),
dΦB/dt = 9.75 × 10^-3•ω Cos(ωt)
So,
ε = —NdΦB/dt
ε = —110 × 9.75 × 10^-3•ω Cos(ωt)
Since ω = 91.11 rad/s
ε = —110 × 9.75 × 10^-3 ×91.11 Cos(91.11t)
ε = —97.71 Cos(91.11t)
The EMF as a function of time is
ε = —97.71 Cos(91.11t)
Extra
The maximum EMF will be when Cos(91.11t) = -1
Then, maximum emf = 97.71V