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Aleks04 [339]
3 years ago
7

What is the mass of 22.4 L of O2 at STP? (5 points)

Chemistry
2 answers:
egoroff_w [7]3 years ago
4 0

Explanation:

explanation :  -  \\  \\ volume \: of \: 1 \: mole \: of \: a \: gas \:  \\  \\ at \: stp \: is \: 22.4 \: litre \\  \\ so \:  \:  \: number \: of \: moles \: of \: oxygen \:  \\  \\  = 1 \: moles \:  \\  \\ hence \: the \: mass \: of \: one \: mole \:  \\  = 1 \: mole \:  \\  \\ mass \: of \: 1 \: mole \: of \: oxygen \: \\  \\   =  > 15.99 \: grams \:  \:  \: (answer) \\  \\ hope \: it \: helps \: \:  \:  (. ❛ ᴗ ❛.)

Paha777 [63]3 years ago
4 0

Answer:

31.99 g O2

Explanation:

Any gas at STP has a molar volume of 22.4 L/mol. This may be an amount you want to memorize.

 

(given volume) * (molar volume)= moles of O2

22.4 L * \frac{1 mol}{22.4 L}= 1 mol O2

Now we can convert moles of O2 to grams using the molar mass of O2.

(moles of O2) * (molar mass of O2)= grams of O2

1 mol * \frac{31.99 g}{1 mol} = 31.99g

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