Question

What is the mass of 22.4 L of O2 at STP? (5 points)

Answer 1

Explanation:

$explanation : - \\ \\ volume \: of \: 1 \: mole \: of \: a \: gas \: \\ \\ at \: stp \: is \: 22.4 \: litre \\ \\ so \: \: \: number \: of \: moles \: of \: oxygen \: \\ \\ = 1 \: moles \: \\ \\ hence \: the \: mass \: of \: one \: mole \: \\ = 1 \: mole \: \\ \\ mass \: of \: 1 \: mole \: of \: oxygen \: \\ \\ = > 15.99 \: grams \: \: \: (answer) \\ \\ hope \: it \: helps \: \: \: (. ❛ ᴗ ❛.)$

Answer 2

Answer:

31.99 g O2

Explanation:

Any gas at STP has a molar volume of 22.4 L/mol. This may be an amount you want to memorize.

 

(given volume) * (molar volume)= moles of O2

$22.4 L * \frac{1 mol}{22.4 L}= 1 mol O2$

Now we can convert moles of O2 to grams using the molar mass of O2.

(moles of O2) * (molar mass of O2)= grams of O2

$1 mol * \frac{31.99 g}{1 mol} = 31.99g$