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astraxan [27]
3 years ago
10

8. (Liquids, Gas) have no definite shape, and no definite volume. A)Liquid B)Gas

Physics
1 answer:
Fynjy0 [20]3 years ago
4 0
B. gas has no definite shape or volume. liquid has definite volume but no definite shape
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A van of mass 1200kg is moving with speed of 90km/hr. It is brought in 3 seconds by applying brakes. Calculate the force applied
Dimas [21]

Answer:

Explanation:

The main equation to solve this is F = ma, where F is the force applied to the brakes with respect to its acceleration. We have the mass that we need, but we do not have the acceleration. That's the first thing we have to find. However, our velocity needs to be stated in m/s and right now it's in km/h. Converting that:

90\frac{km}{hr}*\frac{1000m}{1km}*\frac{1hr}{3600s} =25\frac{m}{s} Now we're ready to find the acceleration:

a=\frac{v_f-v_0}{t} where the top line there translates to the final velocity minus the initial velocity.

a=\frac{0-25}{3.0} so the acceleration is -8.3 m/s/s

We can use that now in the force equation above:

F = 1200(-8.3) and

F = -1.0 × 10⁴ N (that's 10,000 N to the correct number of sig dig's; the negative sign means that the force is being applied in the direction opposite to that which the van is currently moving)

4 0
3 years ago
the earth's moon has a gravitational field strength of about 1.6 n/kg near its surface. the moon has a mass of 7.35x10^22 kg. wh
REY [17]

Answer:

1737 kilometers

7 0
3 years ago
(a) What net external force is exerted on a 1100.0-kg artillery shell fired from a battleship if the shell is accelerated at 2.4
MAVERICK [17]

Explanation:

It is given that,

Mass of the artillery shell, m = 1100 kg

Acceleration of he shell, a=2.4\times 10^4\ m/s^2

(a) The magnitude of force exerted on the shell can be calculated using Newton's second law of motion as :

F = ma

F=1100\ kg\times 2.4\times 10^4\ m/s^2

F = 26400000 N

or

F=2.6\times 10^7\ N

(b) The magnitude of the force exerted on the ship by the artillery shell will be same but the direction is opposite as per Newton's third law of motion. i.e 2.6\times 10^7\ N

7 0
4 years ago
A student connects three AA batteries (1.5 V each) in series to light up a light bulb. The circuit has a resistance of 35 Ω. How
marissa [1.9K]

Answer:

0.13A

Explanation:

Given parameters:

Number of batteries  = 3

Voltage of each batter  = 1.5V

Voltage of the circuit  = 3 x 1.5  = 4.5V

Resistance  = 35Ω

Unknown:

Current that flows in the circuit  = ?

Solution:

According to Ohm's law;

             I  = \frac{V}{R}  

I is the current

V is the voltage

R is the resistance

 Now insert the parameters and solve;

             I  = \frac{4.5}{35}   = 0.13A

8 0
3 years ago
Bob is pushing a lawn mower up a hill with the mower tilting slightly to the right. suppose that we wish to use vectors to deter
jok3333 [9.3K]
Bob is pushing a lawn mower up a hill with the mower tilting slightly to the right. If we wish to use vectors to determine the total force acting on the mower. These are the forces that should be considered:

Force pushing the lawnmower <span>
Gravitational force 
Weight of the lawnmower pushing against the slope 
<span>Counter force of the slope against the lawnmower</span></span>

3 0
4 years ago
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