Explanation:
6a) Work = force × distance
W = Fd
W = (60 N) (10 m)
W = 600 J
6b) Change in energy = work
ΔKE = 600 J
7a) Kinetic energy is half the mass times the square of the velocity.
KE = ½ mv²
KE = ½ (0.4 kg) (25 m/s)²
KE = 125 J
7b) Work = change in energy. When the ball is stopped, it has zero kinetic energy.
W = ΔKE
W = 0 J − 125 J
W = -125 J
Do you have any options? My guess would be distance but I could be wrong.
Speed is just how fast the object is moving, while velocity is the speed and <em>direction </em>of the object.
edit* Direction would be something such as North, East, etc.
Answer:
Final speed of striped ball is 3 m/s in left direction .
Explanation:
Given :
Two billiard ball with the same mass moves toward the left at the same speed 3 m/s .
Let , us assume right hand side direction to be positive and left hand side direction to be negative .
Also , let speed of ball after collision is (striped ball ) u and (solid ball) v .
It is also given that the collision is elastic .
Therefore , kinetic energy is conserved .
...... ( 1 )
Also , by conserving linear momentum .
We get :
...... ( 2 )
Putting value of u from equation 2 to equation 1 .
We get :
And , u = -3 m/s .
Therefore , final speed of striped ball is 3 m/s in left direction .
Hence , this is the required solution .
Answer:
For C1, Q = 1.6125×10⁻³ C
For C2, Q = 6.25×10⁻⁴ C
Explanation:
Note: Since the capacitors are connected in parallel, The voltage across each of them is equal.
From the question,
Q = CV........................ Equation 1
Where Q = Charge on the capacitor, V = Voltage across the capacitor, C = Capacitance of the capacitor.
For the first capacitor,
Q = C1V............. Equation 2
Where C1 = 6.45 μF= 6.45×10⁻⁶ F, V = 250 V
Substitute into equation 2
Q = (6.45×10⁻⁶ )(250)
Q = 1.6125×10⁻³ C.
For the the second capacitor,
Q = C2V............. Equation 3
Given: C2 = 2.50 μF = 2.5×10⁻⁶ F, V = 250 V
Q = (2.5×10⁻⁶ )(250)
Q = 6.25×10⁻⁴ C
