Answer:
The ground exerts an equal force on the golf ball
Explanation:
Third's Newton Law states that:
"When an object A exerts a force on an object B, then object B exerts an equal and opposite force on object A".
In this problem, object A is the golf ball while object B is the ground, so we can say that:
- the golf ball exerts a force on the ground
- the ground exerts an equal and opposite force on the golf ball
Answer:
Explanation:
A ) angular velocity ω = 2π / T
= 2 x 3.14 / 60
= .10467 rad / s
linear velocity v = ω R
= .10467 x 50
= 5.23 m / s
centripetal force = m v² / R
= mg v² / gR
= 834 x 5.23² / 9.8 x 50
= 46.55 N
B )
apparent weight
= mg - centripetal force
= 834 - 46.55
= 787.45 N
C ) apparent weight
= mg + centripetal force
= 834 + 46.55
= 880.55 N.
D )
For apparent weight to be zero
centripetal force = mg
mg = mv² / R
v² = gR
= 9.8 x 50
= 490
v = 22.13 m /s
time period of revolution
= 2π R /v
2 x 3.14 x 50 / 22.13
= 14.19 s
To solve this problem it is necessary to apply the concepts related to frequency as a function of speed and wavelength as well as the kinematic equations of simple harmonic motion
From the definition we know that the frequency can be expressed as
Where,
Therefore the frequency would be given as
The frequency is directly proportional to the angular velocity therefore
Now the maximum speed from the simple harmonic movement is given by
Where
A = Amplitude
Then replacing,
Therefore the maximum speed of a point on the string is 3.59m/s
