Answer:
the mass required to inflate a 72 L bag is 191.491 g
Explanation:
reaction:
conditions:
- V = 72.0 L
- STP: P = 1 atm ∧ T = 298 K
gas law:
- PV = RTn
- R = 0.082 atm * L / K * mol
⇒ n = PV / RT
⇒ n = ((1 atm) * ( 72.0 L)) / (0.082 atm*L / K*mol) * (298 K)
⇒ n = 2.946 mol
⇒ m = n * Mw = ( 2.946 mol ) * ( 64.99 g/mol)
⇒ m = 191.491 g
True, because a liquid can be taken and added, but a solid stay the same never losses and never gains
Answer:
Hello there!
The first answer is hot
The second answer is sunshine!
Explanation:
Those make the most sense
Have a great day!
The amount of heat deposited on the skin is 2.26 kJ.
<h3>What is the amount of heat given off by 1.0 g of steam?</h3>
The amount of heat given off by steam is determined using the formula below:
Quantity of heat = mass * latent heat of vaporization.
Moles of steam = 1.0/18
Heat = 1.0/18 * 40.7
Heat deposited = 2.26 kJ
In conclusion, the quantity of heat is determined from the latent heat of vaporization and the moles of steam.
Learn more about heat of vaporization at: brainly.com/question/26306578
#SPJ1
Answer:
saturated fats
Explanation:
bcoz it is solid at room temperature and does not have double bonds between carbons
