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gogolik [260]
3 years ago
6

What is Darwin's name for species that do not appear to have changed for millions of years?

Chemistry
1 answer:
ioda3 years ago
4 0

Since, the options have not been given the question is incomplete.

What is Darwin's name for species that do not appear to have changed for millions of years?

a.

Dinosaurs

b.

Living fossils

c.

Old souls

d.

Ancient moderns

Answer: b. Living fossil

Explanation:

In 1859 Charles Darwin proposed the term living fossil, that means a species or group of species that had not changed in terms of evolutionary context thus can be useful in tracing the extinct or previously existing forms of life. The examples of the living fossils are horseshoe crabs, ginkgo (Conifers) and tuatara. These group of animals were existed unchanged in the Ordovician, Permian, and Triassic periods respectively with few surviving species.

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A compound that contains only carbon, hydrogen, and oxygen is 58.8% C and 9.87% H by mass. What is the empirical formula of this
Dmitry [639]

<u>Answer:</u> The empirical formula of the compound becomes C_5H_{10}O_2

<u>Explanation:</u>

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

Let the mass of the compound be 100 g

Given values:

% of C = 58.8%

% of H = 9.87%

% of O = [100 - 58.8 - 9.87] = 31.33%

Mass of C = 58.8 g

Mass of H = 9.87 g

Mass of O = 31.33 g

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Molar mass of C = 12 g/mol

Molar mass of H = 1 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of C}=\frac{58.8g}{12g/mol}=4.9 mol

\text{Moles of H}=\frac{9.87g}{1g/mol}=9.87 mol

\text{Moles of O}=\frac{31.33g}{16g/mol}=1.96mol

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 1.96 moles

\text{Mole fraction of C}=\frac{4.9}{1.96}=2.5

\text{Mole fraction of H}=\frac{9.87}{1.96}=5.03\approx 5

\text{Mole fraction of O}=\frac{1.96}{1.96}=1

Converting the mole fraction into whole numbers by multiplying them with 2.

\text{Mole fraction of C}=2.5\times 2=5

\text{Mole fraction of H}=5\times 2=10

\text{Mole fraction of O}=1\times 2=2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 5 : 10 : 2

Hence, the empirical formula of the compound becomes C_5H_{10}O_2

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Which is true about scientific knowledge
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3. Dorji was provided with four colourless solutions. He was asked to
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Answer:

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The reason that Noble Gases do not react is because
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Answer:

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What are physical and chemical properties of boron?
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The chemical properties of boron are more similar to carbon and silicon than elements of its own group, although boron is more electron deficient. Boron has a high affinity for oxygen-forming borates, and reacts with water at temperatures above 100 °C to form boric acid and other boron compounds.”

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