Question

Charge of uniform linear density (4.0 nC/m) is distributed along the entire x axis. Determine the magnitude of the electric field on the y axis at y = 2.5 m

Answer 1

Answer:

The Magnitude of electric field is  $E =29 N/C$

Explanation:

From the question we are told that

     The  uniform linear density is $\lambda = 4.0nC/m$

      The distance on the y-axis is $d = 2.5m$

Generally electric field is mathematically represented as

                                $E =\frac{\lambda}{2 \pi r \epsilon_o d }$

Where $\epsilon_o$ is the permitivity of free space given as $\epsilon_0 = 8.85*10^{-12} C^2 /N \cdot m^2$

Substituting values

                          $E= \frac{1}{2} * 3.142 * 8.85*10^{-12} * \frac{4.0*10^{-9}}{2.5}$

                               $= 29N/C$