Answer:
0.200 m K3PO3
Explanation:
Let us remember that the freezing point depression is obtained from the formula;
ΔTf = Kf m i
Where;
Kf = freezing point constant
m = molality
i = Van't Hoff factor
The Van't Hoff factor has to do with the number of particles in solution. Let us consider the Van't Hoff factor for each specie.
0.200 m HOCH2CH2OH - 1
0.200 m Ba(NO3)2 - 3
0.200 m K3PO3 - 4
0.200 m Ca(CIO4)2 - 3
Hence, 0.200 m K3PO3 has the greatest van't Hoff factor and consequently the greatest freezing point depression.
Convert temperature to Kelvin
Convert vol to L
Apply Charles law
- V1T_2=V2T_1
- 0.4(400)=498V_2
- 160=498V_2
- V_2=0.32L=320mL
One mole of oxygen gas, which has the formula O2, has a mass of 32 g and contains 6.02 X 1023 molecules of oxygen but 12.04 X 1023 (2 X 6.02 X 1023) atoms, because each molecule of oxygen contains two oxygen atoms.
<u>Answer:</u> The total pressure inside the container is 77.9 kPa
<u>Explanation:</u>
Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.
To calculate the total pressure inside the container, we use the law given by Dalton, which is:

We are given:
Vapor pressure of oxygen gas,
= 40.9 kPa
Vapor pressure of nitrogen gas,
= 23.3 kPa
Vapor pressure of argon,
= 13.7 kPa
Putting values in above equation, we get:

Hence, the total pressure inside the container is 77.9 kPa
Answer:

Explanation:
Hello!
In this case, as we know the mass of the total sample, we can first compute the mass of oxygen:

Next, we compute the moles of each element:

Now, we divide the moles by 0.184 moles, the fewest ones, to obtain:

Therefore, the empirical formula is:

Regards!