Answer:
16 meters
Step-by-step explanation:
The height function is given by:
The value of x, in seconds, for which the derivate of the height function is zero, is the time at which the maximum height occurs:
For x = 3 seconds, the height is:
The maximum height that the ball will reach is 16 meters.
For your first answer 2=x+5/17 your second answer is 29. This is because "x" is the number that you need to bake which is 29. Therefore, 31/17=2
Answer:
slope= 0.2; intercept=-1; slope-interception form: y=0.2x-1.
Step-by-step explanation:
1) if to re-write the given equation, then
or y=0.2x-1;
this equation is slope-interception form;
2) according to the new view of the equation,
the required slope is 1/5;
the required y-intercept is -1.
Answer:
.
Step-by-step explanation:
Answer:
f(t) = 15.06 m
Step-by-step explanation:
The relationship between the height of the rocket and the time after launch, t. In seconds is given by :
We need to find the maximum height the rocket will reach the ground.
When it reaches the ground,
f(t) = 0
So,
Maximum height,
f'(t) = 0
Put t = 1.63 in equation (1).
So, the maximum height of the rocket is 15.06 m.