Answer:
a) 0.61 mol
Explanation:
165.3718 g Rubidium Bromide = 1 mol
100 g Rubidium Bromide = 1/165.3718 x 100
= 0.61 mol
Answer:
3.91 L
Explanation:
Using the ideal gas law equation as follows:
PV = nRT
Where:
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
Based on the information given in this question,
P = 5.23 atm
V= ?
n = 0.831 mol
T = 27°C = 27 + 273 = 300K
Using PV = nRT
V = nRT/P
V = (0.831 × 0.0821 × 300) ÷ 5.23
V = 20.47 ÷ 5.23
V = 3.91 L
Answer:
V = 0.0327 L.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the liters of C3H6O by the definition of density. We can tell the density of this substance as that of acetone (0.784 g/mL) and therefore calculate the liters as shown below:
Regards!
Answer:
Potassium dihydrogen phosphate is a potassium salt in which dihydrogen phosphate(1-) is the counterion. ... It is a source of phosphorus and potassium as well as a buffering agent. It can be used in fertilizer mixtures to reduce escape of ammonia by keeping pH low.
Explanation:
