Carbon has an electron configuration of 1s^2 2s^2 2p^2. During sp hybridization, one s and one p orbital of carbon combine to form two sp hybrid orbitals.
Answer:
Clay soil
Explanation:
There are basically three types of soil namely: Sandy soil, clayey soil and loamy soil. Each of this soil type possess their own distinguishing characteristics. For example, on the basis of particle size and texture, CLAY SOIL possesses the smallest and finest particles.
Particles in a clay soil weighs lesser than 0.002 millimeters (mm) in size, making it have a high water holding or retention capacity.
Answer:
ΔS° = 180.5 J/mol.K
Explanation:
Let's consider the following reaction.
4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g)
The standard molar entropy of the reaction (ΔS°) can be calculated using the following expression.
ΔS° = ∑np × S°p - ∑nr × S°r
where,
ni are the moles of reactants and products
S°i are the standard molar entropies of reactants and products
ΔS° = 4 mol × S°(NO(g)) + 6 × S°(H₂O(g)) - 4 mol × S°(NH₃(g)) - 5 mol × S°(O₂(g))
ΔS° = 4 mol × 210.8 J/K.mol + 6 × 188.8 j/K.mol - 4 mol × 192.5 J/K.mol - 5 mol × 205.1 J/K.mol
ΔS° = 180.5 J/K
This is the change in the entropy per mole of reaction.
