Answer:
I think it's a triangle
Step-by-step explanation:
hope this helped
![\huge \boxed{\mathfrak{Answer} \downarrow}](https://tex.z-dn.net/?f=%20%5Chuge%20%5Cboxed%7B%5Cmathfrak%7BAnswer%7D%20%5Cdownarrow%7D)
![\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\](https://tex.z-dn.net/?f=%20%5Clarge%20%5Cbf%5Cfrac%20%7B%205%20-%203%20i%20%7D%20%7B%20-%202%20-%209%20i%20%7D%20%5C%5C%20)
Multiply both numerator and denominator of
by the complex conjugate of the denominator, -2+9i.
![\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)}) \\](https://tex.z-dn.net/?f=%20%5Clarge%20%5Cbf%20%5C%3A%20Re%28%5Cfrac%7B%5Cleft%285-3i%5Cright%29%5Cleft%28-2%2B9i%5Cright%29%7D%7B%5Cleft%28-2-9i%5Cright%29%5Cleft%28-2%2B9i%5Cright%29%7D%29%20%20%5C%5C%20)
Multiplication can be transformed into difference of squares using the rule:
.
![\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}}) \\](https://tex.z-dn.net/?f=%20%5Clarge%20%5Cbf%20%5C%3A%20Re%28%5Cfrac%7B%5Cleft%285-3i%5Cright%29%5Cleft%28-2%2B9i%5Cright%29%7D%7B%5Cleft%28-2%5Cright%29%5E%7B2%7D-9%5E%7B2%7Di%5E%7B2%7D%7D%29%20%20%5C%5C%20)
By definition, i² is -1. Calculate the denominator.
![\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85}) \\](https://tex.z-dn.net/?f=%20%5Clarge%20%5Cbf%20%5C%3A%20Re%28%5Cfrac%7B%5Cleft%285-3i%5Cright%29%5Cleft%28-2%2B9i%5Cright%29%7D%7B85%7D%29%20%20%5C%5C%20)
Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.
![\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85}) \\](https://tex.z-dn.net/?f=%20%5Clarge%20%5Cbf%20%5C%3A%20Re%28%5Cfrac%7B5%5Cleft%28-2%5Cright%29%2B5%5Ctimes%20%5Cleft%289i%5Cright%29-3i%5Cleft%28-2%5Cright%29-3%5Ctimes%209i%5E%7B2%7D%7D%7B85%7D%29%20%20%5C%5C%20)
Do the multiplications in
.
![\large \bf \: Re(\frac{-10+45i+6i+27}{85}) \\](https://tex.z-dn.net/?f=%20%5Clarge%20%5Cbf%20%5C%3A%20Re%28%5Cfrac%7B-10%2B45i%2B6i%2B27%7D%7B85%7D%29%20%20%5C%5C%20)
Combine the real and imaginary parts in -10+45i+6i+27.
![\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85}) \\](https://tex.z-dn.net/?f=%20%5Clarge%20%5Cbf%20%5C%3A%20Re%28%5Cfrac%7B-10%2B27%2B%5Cleft%2845%2B6%5Cright%29i%7D%7B85%7D%29%20%20%5C%5C%20)
Do the additions in
.
![\large \bf Re(\frac{17+51i}{85}) \\](https://tex.z-dn.net/?f=%20%5Clarge%20%5Cbf%20Re%28%5Cfrac%7B17%2B51i%7D%7B85%7D%29%20%20%5C%5C%20)
Divide 17+51i by 85 to get
.
![\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i) \\](https://tex.z-dn.net/?f=%20%5Clarge%20%5Cbf%20%5C%3A%20Re%28%5Cfrac%7B1%7D%7B5%7D%2B%5Cfrac%7B3%7D%7B5%7Di%29%20%20%5C%5C%20)
The real part of
is
.
![\large \boxed{\bf\frac{1}{5} = 0.2} \\](https://tex.z-dn.net/?f=%20%20%5Clarge%20%20%5Cboxed%7B%5Cbf%5Cfrac%7B1%7D%7B5%7D%20%3D%200.2%7D%20%5C%5C%20)
Answer:
(58-11) divided by 20
Step-by-step explanation:
Answer: -6 (8-14=-6)
Step-by-step explanation:
8-14 = -6
The correct answer is 2.8 liters
Explanation:
The volume of the water in the bottle can be calculated by subtracting 3.5 liters from the volume of water the pail can hold (6.3 liters) because the volume in the bottle is 3.5 liters less than the one in the pail. Below, you can find the process.
volume in the pail - 3.5 liters = volume in the bottle
6.3 liters - 3.5 liters = 2.8 liters
This means the volume of water in the bottle is 2.8 liters. Also, you can double-check this answer by adding the volume in the bottle and the 3.5 liters (2.8 + 3.5 = 6.3).