The answer is 888+88+8+8+8
The answer is D, tony would always be behind Robert.
Answer:
x = 13sqrt(3) ft = 22.5 ft
y = 13 ft
Step-by-step explanation:
The triangle is a 30-60-90 right triangle.
The ratio of the lengths of the sides is
short leg : long leg : hypotenuse = 1 : sqrt(3) : 2
From the ratio above we see that the hypotenuse is twice the short leg.
The long leg is sqrt(3) times the short leg.
y = short leg
x = long leg
26 ft = hypotenuse
y = 26 ft/2 = 13 ft
x = 13 ft * sqrt(3) = 13sqrt(3) ft = 22.5 ft
Answer:
9 miles
Step-by-step explanation:
mean is calculated as
mean = 
, then
= 5.7 ( multiply both sides by 10 )
sum = 57
let x be the distance he needs to cover so mean is 6 , that is
= 6 ( multiply both sides by 11 )
sum + x = 66 , that is
57 + x = 66 ( subtract 57 from both sides )
x = 9
That is he would have to run 9 miles
Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
