Yes me too lol i agree :)
<h3>
Answer:</h3>
46.67 m/s²
<h3>
Explanation:</h3>
<u>We are given;</u>
- Mass of a rocket = 3 kg
- Force applied = 140 N
we are supposed to calculate the acceleration of the rocket;
- We are going to use the second Newton's law of motion;
- According to Newton's second Law of motion force is equivalent to the product of mass and acceleration.
- This is from the fact that the resultant force and the rate of change in linear momentum are directly proportional.
Therefore;
F = Ma
In this case;
Rearranging the formula
a = F ÷ m
= 140 N ÷ 3 kg
= 46.67 m/s²
Thus, the acceleration of the rocket is 46.67 m/s²
Answer:
The average power is 15.26 W.
Explanation:
Given that,
Force = 29 N
Radius = 0.27 m
Time = 1.9 s
We need to calculate the power
Using formula of power
![P=\dfrac{W}{t}](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7BW%7D%7Bt%7D)
![P=\dfrac{F\cos\theta \times s}{t}](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7BF%5Ccos%5Ctheta%20%5Ctimes%20s%7D%7Bt%7D)
![P=\dfrac{F\cos\theta\times 2\pi r}{t}](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7BF%5Ccos%5Ctheta%5Ctimes%202%5Cpi%20r%7D%7Bt%7D)
Here, ![\theta=0^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D0%5E%7B%5Ccirc%7D)
Where, F = force
t = time
r = radius
Put the value into the formula
![P=\dfrac{29\cos0\times2\pi\times0.27}{1.9}](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7B29%5Ccos0%5Ctimes2%5Cpi%5Ctimes0.27%7D%7B1.9%7D)
![P=15.26\ W](https://tex.z-dn.net/?f=P%3D15.26%5C%20W)
Hence, The average power is 15.26 W.
Answer:
I think you ask for another way of writing the joule (J). It can be expressed as the product between a force applied to a body and the deployment of the body (not necessarily caused by that force applied), so N*m (newton * meter).
Answer:
<h2>
40 seconds</h2>
Solution,
![p = \frac{w}{t} \\ or \: 30 = \frac{1200}{t} \\ or \: 30 \times t = 1200 \\ or \: t = \frac{1200}{30} \\ t = 40 \: seconds](https://tex.z-dn.net/?f=p%20%3D%20%20%5Cfrac%7Bw%7D%7Bt%7D%20%20%5C%5C%20or%20%5C%3A%2030%20%3D%20%20%5Cfrac%7B1200%7D%7Bt%7D%20%20%5C%5C%20or%20%5C%3A%2030%20%5Ctimes%20t%20%3D%201200%20%5C%5C%20or%20%5C%3A%20t%20%3D%20%20%5Cfrac%7B1200%7D%7B30%7D%20%20%5C%5C%20t%20%3D%2040%20%5C%3A%20seconds)
Hope this helps..
Good luck on your assignment.