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dedylja [7]
3 years ago
11

Andre is packing for a move to Kentucky. He needs to pack 20 small paperback books whose total mass is 5 kg and some pillows who

se total mass is 5kg. Which will need the larger box?
Chemistry
1 answer:
storchak [24]3 years ago
6 0
The pillows because it is larger than paperback books, in this situation just think about which is larger, I pretty sure Andre is not going to hold the boxes in his hand. 
hope I helped
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The rate constant, k, for a reaction is 0.0354 sec1 at 40°C. Calculate the rate constant for the
deff fn [24]

Answer:

The rate constant of the reaction at 125˚ is 0.3115 \ \text{sec}^{-1}.

Explanation:

The Arrhenius equation is a simple equation that describes the dependent relationship between temperature and the rate constant of a chemical reaction. The Arrhenius equation is written mathematically as

                                                  k \ = \ Ae^{\displaystyle\frac{-E_{a}}{RT}}

                                               \ln k \ = \ \ln A \ - \ \displaystyle\frac{E_{a}}{RT}

where k is the rate constant, E_{a} represents the activation energy of the chemical reaction, R is the gas constant, T is the temperature, and A is the frequency factor.

The frequency factor, A, is a constant that is derived experimentally and numerically that describes the frequency of molecular collisions and their orientation which varies slightly with temperature but this can be assumed to be constant across a small range of temperatures.

Consider that the rate constant be k_{1} at an initial temperature T_{1} and the rate constant k_{2} at a final temperature T_{2}, thus

                         \ln k_{2} \ - \ \ln k_{1} = \ \ln A \ - \ \displaystyle\frac{E_{a}}{RT_{2}} \ - \ \left(\ln A \ - \ \displaystyle\frac{E_{a}}{RT_{1}}\right) \\ \\ \\ \rule{0.62cm}{0cm} \ln \left(\displaystyle\frac{k_{2}}{k_{1}}\right) \ = \ \displaystyle\frac{E_{a}}{R}\left(\displaystyle\frac{1}{T_{1}} \ - \ \displaystyle\frac{1}{T_{2}} \right)

                                         \rule{1.62cm}{0cm} \displaystyle\frac{k_{2}}{k_{1}} \ = \ e^{\displaystyle\frac{E_{a}}{R}\left(\displaystyle\frac{1}{T_{1}} \ - \ \displaystyle\frac{1}{T_{2}} \right)} \\ \\ \\ \rule{1.62cm}{0cm} k_{2} \ = \ k_{1}e^{\displaystyle\frac{E_{a}}{R}\left(\displaystyle\frac{1}{T_{1}} \ - \ \displaystyle\frac{1}{T_{2}} \right)}

Given that E_{a} \ = \ 26.5 \ \ \text{kJ/mol}, R \ = \ 8.3145 \ \ \text{J mol}^{-1} \ \text{K}^{-1}, T_{1} \ = \ \left(40 \ + \ 273\right) \ K, T_{2} \ = \ \left(125 \ + \ 273\right) \ K, and k_{1} \ = \ 0.0354 \ \ \text{sec}^{-1}, therefore,

           k_{2} \ = \ \left(0.0354 \ \ \text{sec}^{-1}\right)e^{\displaystyle\frac{26500 \ \text{J mol}^{-1}}{8.3145 \ \text{J mol}^{-1} \ \text{K}^{-1}}\left(\displaystyle\frac{1}{313 \ \text{K}} \ - \ \displaystyle\frac{1}{398 \ \text{K}} \right)} \\ \\ \\ k_{2} \ = \ 0.3115 \ \ \text{sec}^{-1}                      

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Answer:

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15. What is true about concentration of a solution? *
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<h3>Answer:</h3>

A saturated solution is a chemical solution containing the maximum concentration of a solute dissolved in the solvent.

<h3>Explanation:</h3>
  • A solution is made by dissolving a solute in a solvent.
  • For example dissolving a salt in a solvent such as water results to a solution.
  • Solution may either be saturated or unsaturated.
  • Unsaturated solution is a solution that can dissolve more solute upon addition because it has not reached saturation.
  • A saturated solution on the other hand is a solution that has maximum solute and the concentration of solute is maximum and thus the solvent can not dissolve any more solute.
  • Therefore, a saturated solutions contain maximum concentration of a solute dissolved in the solute.
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2H3PO4 +3Ca(OH) 2 = Ca3 (PO4) 2 +6H20

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