Answer:
The answer is
<h2>[OH-] = 1.66 × 10^-14 M</h2>
Explanation:
To find the [OH-] we must first find the pH and the pOH of the solution
That's
pH + pOH = 14
pOH = 14 - pH
To find the pH we use the formula
pH = -log [H3O+]
From the question
[H3O+] = 0.6 M
pH = - log 0.6
pH = 0.22
pOH = 14 - 0.22
pOH = 13.78
We can now find the [OH -] in the solution using the formula
pOH = - log [OH-]
13.78 = - log [OH-]
Find the antilog of both sides
We have the final answer as
<h3>[OH-] = 1.66 × 10^-14 M</h3>
Hope this helps you
1 gold(lll), 3 fluorine
This is because of the good has a 3+ charge and the fluorine has a 1- charge so they have to balance each other out
<u>Answer:</u> The volume of stock solution of ammonia that is needed is 48.67 mL
<u>Explanation:</u>
To calculate the volume of stock solution, we use the equation:
where,
are the molarity and volume of the stock ammonia solution
are the molarity and volume of diluted ammonia solution
We are given:
Putting values in above equation, we get:
Hence, the volume of stock solution of ammonia that is needed is 48.67 mL
The planet would be Uranus.
