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vladimir1956 [14]

2 years ago

8

A taxi company charges $2.25 for the first 5 miles and $0.75 for each mile. If a passenger spent $6 on a trip, how many miles di

d he travel? Write an equation to solve.

1 answer:

natka813 [3]2 years ago

4 0

$2.25 for the first 5 miles

0.75 + 0.75 + 0.75 + 0.75 + 0.75 = 3.75

3.75 + 2.25 = 6

5 + 5 = 10

He travelled 10 miles

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You and a friend tutor for a total of 12 hours. Use the tape diagram to find how many hours you tutor.

kirill [66]

Answer: YOU TUTOR 9 HOURS

Step-by-step explanation: EACH BOX REPRESENTS 3 HOURS I THINK, SO YOU TUTOR NINE HOURS AND YOUR FRIEND TUTORS 3 HOURS.

3X3=9

1X3=3

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2 years ago

Graph f(x)=2^x+1 and g(x)=−x+4 on the same coordinate plane.

12345 [234]

Given f(x)= 2^x +1

g(x)= -x +4

We have to find the value of x which satisfy the condetion : f(x)= g(x)

Solution : let us place expression given for f(x) and g(x) equal to each other

This gives us : 2^x + 1 = -x+ 4

Let us bring all x terms on left side only

we add x on both sides this makes : 2^x +1 +x = -x+ 4 +x

on the right side -x and +x becomes a "0"

we get : 2^x + 1 + x = 4

* let us nopw bring all the numeric terms on left side only

subtract 1 from both sides : 2^x + 1 + x - 1 = 4- 1

on the left side +1 and -1 becomes a "0"

on the rigth side 4-1 becomes a "3"

equation look like : 2^x + x = 3

We can see the right side is an odd number

on the left side there is sum of two terms one of them is 2^x which is an even number always .

we know that sum of an even number with an even number result out an even number

but we want a result as an odd number (3)

this suggest that x should be an odd number .

Also the sum of 2^x and x is 3 so 2^x should be smaller than 3

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8 0

2 years ago

Read 2 more answers

Ray delivered 3/8 of the newspapers on his route in the first hour and 4/5 of the rest in the second hour what fraction of the n

Temka [501]

Answer:

$\frac{1}{2}$

Step-by-step explanation:

Let the total number of Newspapers be x

Number of newspapers delivered in first hour of his route= $\frac{3}{8}$ of x

Total number of newspapers delivered in first hour= $\frac{3}{8}$ x

Number of newspapers left= x- $\frac{3x}{8}$

Number of newspapers left= $\frac{8x-3x}{8}$

Number of newspapers left= $\frac{5x}{8}$

Number of newspapers delivered in second hour=4/5 of $\frac{5x}{8}$

Number of newspapers delivered in second hour= $\frac{x}{2}$

Fraction of newspapers delivered in second hour is= $\frac{1}{2}$

Hence, the correct answer is $\frac{1}{2}$

8 0

3 years ago

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, <u><em>the test statistics</em></u> = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

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3 years ago

Los divisores de 100 son tambien divisores de 50 ?

sergiy2304 [10]

Answer:

La afirmación es falsa, no todos los divisores de 100 son divisores de 50, ya que solo se toman en cuenta sus divisores comunes, los cuales son todos los divisores de 50. Expresamos a 100 en sus factores primos: 100 = 2 · 2 · 5 · 5 = 2² · 5² Divisores de 100: {1, 2, 4, 5, 10, 20, 25, 50, 100}

Step-by-step explanation:

8 0

2 years ago