The solution would be like
this for this specific problem:
<span>
The force on m is:</span>
<span>
GMm / x^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2] ->
1
The force on 2m is:</span>
<span>
GM(2m) / (L - x)^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2]
-> 2
From (1), you’ll get M = 2mx^2 / L^2 and from
(2) you get M = m(L - x)^2 / L^2
Since the Ms are the same, then
2mx^2 / L^2 = m(L - x)^2 / L^2
2x^2 = (L - x)^2
xsqrt2 = L - x
x(1 + sqrt2) = L
x = L / (sqrt2 + 1) From here, we rationalize.
x = L(sqrt2 - 1) / (sqrt2 + 1)(sqrt2 - 1)
x = L(sqrt2 - 1) / (2 - 1)
x = L(sqrt2 - 1) </span>
= 0.414L
<span>Therefore, the third particle should be located the 0.414L x
axis so that the magnitude of the gravitational force on both particle 1 and
particle 2 doubles.</span>
Answer:
If it had more or less mass, the atmosphere would be very different with either too much ammonia and methane or too little oxygen and water
Explanation:
Answer:

Explanation:
Given:
- mass of solid cylinder,

- diameter of cylinder,

- mass of bucket of water,

<em>When the bucket is released to fall in the well, it fall under the acceleration due to gravity.</em>
We have formula for angular acceleration as:

where:
g = acceleration due to gravity
r = radius of the cylinder


i think its b cause if you were talking about ice it freezes the melts the evaporates to gas
Answer:
nodding of head ,yes- static equilibrium
nodding of head, no- dynamic equilibrium.
Explanation:
static equilibrium monitors head position when body is not moving .
dynamic equilibrium monitors the angular or rotational movements of the head when body moves.