Question

A cog system on the beginning segment of a roller coaster needs to get 29 occupied cars up a 120-m vertical rise over a time interval of 60 s. Each car experiences a gravitational force of 5900 N. The cars start at rest and end up moving at 0.50 m/s.

Answer 1

Answer:

Hello your question has some missing part attached below is the missing part

How much work is done by the cog system on the cars?

answer : 2.053 * 10^7 J

Explanation:

Total weight of car ( wT )  = 5900 * 29 = 171100 N

mass of car ( mT ) = wT / g  = 171100 / 9.81 = 17459.18 kg

Hence work done by the cog system on the cars

W = ( KE$_{2}$ + PE$_{2}$ ) - ( KE$_{1}$ + PE$_{1}$ )

    = ( 1/2 mv^2 + mgh ) - ( 0 )

    = ( 1/2 * 17459.18 * 0.50^2) + ( 17459.18 * 9.81 * 120 )

    = 2.053 * 10^7 J