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vladimir1956 [14]
3 years ago
12

Bohr's model is sometimes called the ________ model because it resembles a mini-solar system.

Physics
2 answers:
elena-14-01-66 [18.8K]3 years ago
7 0
His model was also called the Planetary model
CaHeK987 [17]3 years ago
7 0

Answer:

Bohr's model is sometimes called the  Rutherford–Bohr model because it resembles a mini solar system.

Explanation:

Early 1900s  Rutherford's model shows that an atom is mostly empty space, with electrons orbiting a fixed, positively charged nucleus in set, predictable paths. This model of an atom was developed by Ernest Rutherford, a New Zealand native working at the University of Manchester in England.

The Bohr Model as presented by Niels Bohr is a planetary model in which the negatively charged electrons orbit a small, positively charged nucleus similar to the planets orbiting the sun (except that the orbits are not planar).

The highlighted similarity between Rutherford and Bohr theory made them similar and a collaboration was been executed by both parties to form  Rutherford-Bohr model.

Thank you

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A pendulum makes 60 vibrations in 15 secs what’s its frequency
o-na [289]

Answer:

4 hertz

Explanation:

The defination of freqyency = the total no of cycle made by a wave in one second .

so,

cycle or vibrations=60

tame taken = 15

now,

frequency = no. of cycle / time taken

= 60/15

=4 hertz

hence, the its frequency = 4hertz

8 0
3 years ago
An ocean wave has an amplitude of 2.5 m. Weather conditions suddenly change such that the wave has an
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Answer:

2.5

Explanation:2.5 +2.5 = 5.0

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3 years ago
What is the mass of a crate if a net force of 12 N gives the crate an acceleration of 0.20 m/s2?
Veseljchak [2.6K]
A :-) for this question , we should apply
F = ma
Given - F = 12 N
a = 0.20 m/s^2
Solution -
F = ma
12 = m x 0.20
m = 12 by 0.20
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.:. The mass is 60 kg.
8 0
2 years ago
A block of mass 2 kg slides down a frictionless ramp of length 1.3 m tilted at an angle 25o to the horizontal. At the bottom of
marin [14]

Answer:

Diagrams in pictures

Explanation:

Using energy I can get

m g h = 1/2 m v^2

So the velocity at the end of the ramp is the squareroot of two times the initial height of the box times the gravity constant.

(H= 1,3m sin25)

V=2,32m/s

V= a t

And

X= v t +1/2 a t^2

Knowing v=2,32 m/s and x= 1,3 m

I can get

a= 6,21m/s2

F= m a

I can get the force of the box when it collides with the spring

F= 12, 425 N

The force the spring makes on the box then is

F = -12,425N = -k d

Then the spring's constant is k= 51,75N/m

To make the two diagrams I need the functions of time when the box slows down

I use the same two equations

V= a t

And

X= v t + 1/2 a t^2

Being now 2,32 my initial velocity and 0 my final velocity, and my distance 0,24 m.

I get there the time t=0,0689 seconds and the acceleration a= -33,67 m/s2 (negative because it's slowing down).

Then,

V(t)= - 33,67 m/s2 t for time between 0 and 0,689 sec

X(t)= 2,32 m/s t + 1/2 33,67 m/s2 t^2.

for time between 0 and 0,689 sec

Diagrams and equations are in the pictures

7 0
3 years ago
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it is a.health record documentation

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