Ask question

Ask question

All categories

Oduvanchick [21]

3 years ago

11

A net force of -1,000 Newtons is delivered to the object over a time of .02 seconds. Calculate the new velocity of the object.

1 answer:

MariettaO [177]3 years ago

4 0

The change in velocity (v₂ - v₁) is

<em> (-20) / (the object's mass)</em>.

Call it a crazy hunch, but I can't shake the feeling that there was more
to the question before the part you copied, that mentioned the object's
mass, and its velocity before this force came along.

You might be interested in

Which energy sources can transfer thermal energy to a heat pump? Check all that apply.

choli [55]

Answer:1.Air, 2.the ground,3.water

Explanation:I just got it right:)

3 0

4 years ago

Where is the safest spot in the house during a tornado, hail storm, and earthquake? Include separate answers.

USPshnik [31]

Answer:

Explanation:

in a room with no windows that way it doesnt shatter. Usually a closet... or if you have a basement.sorry but that applies to all them

4 0

3 years ago

Read 2 more answers

A student travels 4.0m East, 8.0m South, 4.0m west, and finally 8.0m north. What is her displacement? What distance did she trav

erica [24]

no cap bro bro i thinks its poop Explanation:

3 0

3 years ago

A box is being pulled to the right. The free body diagram is shown.What is the magnitude of the kinetic frictional force?

kirill115 [55]

Answer:

A - 0 N

plz mark 5 stars, thanks, and brainliest

4 0

3 years ago

What is the volume V of a sample of 4.00 mol of copper? The atomic mass of copper (Cu) is 63.5 g/mol, and the density of copper

rusak2 [61]

Answer : The volume of a sample of 4.00 mol of copper is $28.5cm^3$

Explanation :

First we have to calculate the mass of copper.

$\text{ Mass of copper}=\text{ Moles of copper}\times \text{ Molar mass of copper}$

$\text{ Mass of copper}=(4.00moles)\times (63.5g/mole)=254g$

Now we have to calculate the volume of copper.

Formula used :

$Density=\frac{Mass}{Volume}$

Now put all the given values in this formula, we get:

$8.92\times 10^3kg/m^3=\frac{254g}{Volume}$

$Volume=\frac{254g}{8.92\times 10^3kg/m^3}=2.85\times 10^{-2}L=2.85\times 10^{-2}\times 10^3cm^3=28.5cm^3$

Conversion used :

$1kg/m^3=1g/L\\\\1L=10^3cm^3$

Therefore, the volume of a sample of 4.00 mol of copper is $28.5cm^3$

7 0

3 years ago

Read 2 more answers