Answer:
47.8% increase, or B since it's the closest.
Step-by-step explanation:
Given:
Number of students who has a cat and a dog = 5
Number of students who has a cat but do not have a dog = 11
Number of students who has a dog but do not have a cat = 3
Number of students who neither have a cat nor a dog = 2
To find:
The probability that a student has a cat given that they do not have a dog.
Solution:
Let the following events:
A = Student has a cat
B = Do not have a dog
Total number of outcomes is:

The probability that a student has a cat but do not have a dog is:

The probability that a student do not have a dog is:


The conditional probability is:



Therefore, the probability that a student has a cat given that they do not have a dog is
.
Answer:
Step-by-step explanation:
x^2+3y/xy
4^2+3*2/4*2
16+6/8
22/8
Answer:
x=-5.5
Step-by-step explanation:
-3(x+4)=(-x-1)
1. Distribute
-3x+(-12)=-x-1
2. Simplify
-3x-12=-x-1
-2x-12=-1
-2x=11
x=-11/2
x=-5.5