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3 years ago

The school orchestra sells snacks

Mathematics

1 answer:

Alex17521 [72]3 years ago

4 0

Answer:

fjfjdidbjcidhd nokichdbd

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What is the weight of a square if a triangle weighs 4 grams? Explain your reasoning

stellarik [79]

Answer:

8 grams

Step-by-step explanation:

The balance is in equilibrium, so the weights of the two sides are equal.

Let the weight of a square be s.

Left side: 2s + 4

Right side: s + 3(4) = s + 12

The weights are equal, so we set the two expressions equal.

2s + 4 = s + 12

s = 8

Answer: The weight of a square is 8 grams.

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4 years ago

Under his cell phone plan, Cameron pays a flat cost of $41 per month and $5 per gigabyte. He wants to keep his bill under $65 pe

hammer [34]

Answer- 512 (hope this helps)

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3 years ago

Jeremy ran 1500 meters in 4 minutes, 45 seconds. How fast did he run in meters per second?

soldi70 [24.7K]

Answer:

5.26 meters per second

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3 years ago

Question 3, help please!

White raven [17]

The answer is not defined.

Explanation:

The given matrix is $\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]+\left[\begin{array}{c}{1} \\ {0}\end{array}\right]$

The matrix $\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]$ has dimensions $2\times 2$

This means that the matrix has 2 rows and 2 columns.

Also, the matrix $\left[\begin{array}{l}{1} \\ {0}\end{array}\right]$ has dimensions $2\times1$

This means that the matrix has 2 rows and 1 column.

Since, the matrices can be added only if they have the same dimensions.

In other words, to add the matrices, the two matrices must have the same number of rows and same number of columns.

Since, the dimensions of the two matrices are not equal, the addition of these two matrices is not possible.

Hence, the addition of these two matrices is not defined.

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3 years ago

Find the sum of this infinite geometric series where a1=0.3 and r=0.55

Lisa [10]

Hello, Marymack!

We know that in a geometric sequence defined by $\mathsf{a_1}$ and $\mathsf{r}$ , the sum can be calculated the following way:

$\mathsf{S_n = \dfrac{a_1}{1-r}}\\ \\ \\ \\ \mathsf{S_n = \dfrac{0.3}{1-0.55}}\\ \\ \\ \mathsf{S_n = \dfrac{0.3}{0.45}}\\ \\ \\ \boxed{\mathsf{S_n = \dfrac{2}{3}=0.666...}}$

3 0

3 years ago

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