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3 years ago

HELP PLEASE EASY I NEED IN 10 MINS PLEASE CMON HELP ILL DO WHATEVER

Mathematics

1 answer:

12345 [234]3 years ago

5 0

Aw.. anyways what’s 16.001 rounded to the nearest tenth- JOKES JOKES

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23x23 Show work please

Arte-miy333 [17]

The awnser would be 23
   x 23
   ____
   529

8 0

2 years ago

Read 2 more answers

The height H of a skydiver t seconds after jumping. Let T be the independent variable, and assume the skydiver jumps from a heig

Rina8888 [55]

Answer:

25 seconds

Step-by-step explanation:

Skydiving.

height (in feet) above the earth=h(t)= -16t^2 + 10,000

the time it would take to fall when h is 0

-16t^2 + 10,000=0

-16t^2=-10000

16t^2=10000

t^2=10000/16=625

t=sqrt 625=25 seconds

6 0

2 years ago

The length of a rectangle is 25 cm.

likoan [24]

Answer:

20<

Step-by-step explanation:

7 0

3 years ago

According to the Rational Root Theorem, which number is a potential root of f(x) = 9x8 + 9x6 – 12x + 7?

notsponge [240]

Answer-

$\boxed{\boxed{\frac{7}{3}}}$

Solution-

Rational Root Theorem-

$f(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+.......+a_1x+a_0\ \ \ and\ a_n\neq 0$

All the potential rational roots are,

$=\pm (\dfrac{\text{factors of}\ a_0}{\text{factors of}\ a_n})$

The given polynomial is,

$f(x) = 9x^8 + 9x^6-12x + 7$

Here,

$a_n=9,\ a_0=7\\\\\text{factors of}\ 9=1,3,9\\\\\text{factors of}\ 7=1,7$

The potential rational roots are,

$=\pm \frac{1}{1},\pm \frac{1}{3}, \pm \frac{1}{9}, \pm \frac{7}{1}, \pm \frac{7}{3}, \pm \frac{7}{9}$

$=\pm 1,\pm \frac{1}{3}, \pm \frac{1}{9}, \pm 7, \pm \frac{7}{3}, \pm \frac{7}{9}$

From, the given options only $\frac{7}{3}$ satisfies.

6 0

2 years ago

Read 2 more answers

An experiment consists of choosing objects without regards to order. Determine the size of the sample space when you choose the

sdas [7]

Answer:

$n= 75, 582$

$n= 2300$

$n = 253$

Step-by-step explanation:

Generally the size of the sample sample space is mathematically represented as

$n = \left N } \atop {}} \right. C_r$

Where N is the total number of objects available and r is the number of objects to be selected

So for a, where N = 19 and r = 8

$n = \left 19 } \atop {}} \right. C_8 = \frac{19 !}{(19 - 8 )! 8!}$

$= \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}$

$n= 75, 582$

For b Where N = 25 and r = 3

$n = \left 25 } \atop {}} \right. C_3 = \frac{25 !}{(19 - 3 )! 3!}$

$= \frac{25 *24 *23 *22 ! }{22 ! \ 3!}$

$n= 2300$

For c Where N = 23 and r = 2

$n = \left 23 } \atop {}} \right. C_2 = \frac{23 !}{(23 - 2 )! 2!}$

$= \frac{23 *22 *21! }{21 ! \ 3!}$

$n = 253$

4 0

3 years ago