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3 years ago

HELP PLEASE EASY I NEED IN 10 MINS PLEASE CMON HELP ILL DO WHATEVER

Mathematics

1 answer:

12345 [234]3 years ago

5 0

Aw.. anyways what’s 16.001 rounded to the nearest tenth- JOKES JOKES

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At the candy store, Sophie filled a bag with 2 2/3 kilograms of candy. 1/4 of the weight of the candy was from chocolate covered

Oksana_A [137]

Answer:

The chocolate covered pretzels in Sophie's bag weighed $\frac{2}{3} = 0.6667$ kilograms.

Step-by-step explanation:

Sophie filled a bag with 2 2/3 kilograms of candy.

This means that the total weight is of:

$2\frac{2}{3} = 2 + \frac{2}{3} = \frac{6}{3} + \frac{2}{3} = \frac{8}{3}$

The total weight is of 8/3 kilograms.

1/4 of the weight of the candy was from chocolate covered pretzels. How much did the chocolate covered pretzels in Sophie's bag weigh?

1/4 of 8/3. So

$\frac{1}{4} \times \frac{8}{3} = \frac{1*8}{4*3} = \frac{2}{3} = 0.6667$

The chocolate covered pretzels in Sophie's bag weighed $\frac{2}{3} = 0.6667$ kilograms.

6 0

3 years ago

City x has a population of 3x10 to the fifth power. City y has a population of 6x10 to the sixth power. Which statement correctl

SVEN [57.7K]

Answer:

Step-by-step explanation:

because it is 3x10 to the 5th power there woould be 5 zeros

5 0

3 years ago

What is the product of 2/3/4 and 1/1/3? Show all the steps.

allochka39001 [22]

Here is how i got my answer.
~Good Luck!~

6 0

4 years ago

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Please help it’s the last question I have left until I can turn this in please answer ASAP if possible

telo118 [61]

Answer:

i cant see

Step-by-step explanation:

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3 years ago

The surface areas of two similar figures are 25 in2 and 36 in2. If the volume of the smaller figure is 250 in3, what is the volu

Slav-nsk [51]

Since the figures are similar, we can establish a rule of three as follows.
We know that the area of the smaller figure is $25in^{2}$ , and its volume is $250in^{3}$ . We also know that the area of the larger figure is $36in^{2}$ ; since we don't now its volume, lets represent it with $X$ :
$\frac{25in^{2}----\ \textgreater \ 250in^{3}}{36in^{2}----\ \textgreater \ Xin^{3}}$
$\frac{25}{36} = \frac{250}{X}$
$X= \frac{(250)(36)}{25}$
$X=360$

We can conclude that the volume of the larger figure is $360in^{3}$ ; therefore, the correct answer is a.

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3 years ago

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