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Arlecino [84]
3 years ago
12

A system of pulleys allows a mechanic to lift an 1800 N engine. If the

Physics
1 answer:
Katyanochek1 [597]3 years ago
4 0

Answer:

1800/600 = 3:1

Explanation:

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(1) In nondestructive testing, a discontinuity may be defined as an interruption in the normal physical structure or configurati
QveST [7]

Answer: BOTH ARE TRUE

Explanation: Nondestructive testing or Evaluation is a term used in the field of science and technology to describe the evaluations, analysis or testing carried out on components of materials without destroying any part or components of the test materials. It is very useful in scientific research or industrial engineering environments. When any disruption of physical structure or configuration of a component will lead to discontinuing of the test, and it may not affect the usefulness of the affected parts.

4 0
3 years ago
Planets that are larger in diameter, farther from the sun, and less dense than smaller planets in the solar system are known as
Sergio [31]
Gas giants lol I'm love this kinda stuff nothing else just this question
6 0
4 years ago
The vapor pressure of ethanol at 293 K is 5.95 kPa and at 336.5 K it is 53.3 kPa. Calculate the enthalpy of vaporization of etha
denis-greek [22]

Answer:

H=41.3kJmol^{-1}

Explanation:

The equation relating the the enthalphy, pressure and temperature is expressed as

ln(\frac{P_{2}}{P_{1}} )=\frac{H}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}} ) \\

Where P is the pressure, H is the enthalphy, and T is the temperature.

since the given values are

T_{1}=293k, \\T_{2}=336.5k\\P_{1}=5.95kPA\\p_{2}=53.3kPA\\and R=8.314J.K^{-1}mol_{-1}

if we insert values, we arrive at

ln(\frac{53.3}{5.95} )=\frac{H}{8.314}(\frac{1}{293}-\frac{1}{336.5} )\\2.19=\frac{H}{8.314}(0.00044)\\H=(2.19*8.314)/0.00044\\H=41,268.8Jmol^{-1}\\H=41.3kJmol^{-1}

4 0
3 years ago
A ball is dropped from a building taking 3sec to fall to the ground. Calculate:
GenaCL600 [577]

Answer:

Vf = 29.4 m/s

h = 44.1 m

Explanation:

Data:

  • Initial Velocity (Vo) = 0 m/s
  • Gravity (g) = 9.8 m/s²
  • Time (t) = 3 s
  • Final Velocity (Vf) = ?
  • Height (h) = ?

==================================================================

Final Velocity

Use formula:

  • Vf = g * t

Replace:

  • Vf = 9.8 m/s² * 3s

Multiply:

  • Vf = 29.4 m/s

==================================================================

Height

Use formula:

  • \boxed{h=\frac{g*(t)^{2}}{2}}

Replace:

  • \boxed{h=\frac{9.8\frac{m}{s^{2}}*(3s)^{2}}{2}}

Multiply time squared:

  • \boxed{h=\frac{9.8\frac{m}{s^{2}}*9s^{2}}{2}}

Simplify the s², and multiply in the numerator:

  • \boxed{h=\frac{88.2m}{2}}

It divides:

  • \boxed{h=44.1\ m}

What is the velocity when falling to the ground?

The final velocity is <u>29.4 meters per seconds.</u>

How high is the building?

The height of the building is <u>44.1 meters.</u>

3 0
3 years ago
A radioactive substance decays according to the formula w = 20e¡kt grams where t is the time in hours. a find k given that after
blagie [28]
W=20 e(-kt)  
A. Rearranging gives k= -(ln(w/20)/t 
 Substituting w= 10 and solving gives k=0.014 
 B. Using W=20e(-kt). After 0 hours, W=20. After 24 hours, W=14.29g. After 1 week (24x7=168h) W=1.9g 
 C. Rearranging gives t=-(ln(10/20)/k. Substituting w=1 and solving gives t=214 hours. 
 D. Differentiating gives dW/ dt = -20ke(-kt). Solving for t=100 gives dW/dt = 0.07g/h. Solving for t=1000 gives 0.0000002g/h 
 E. dW/dt = -20ke(-kt). But W=20e(-kt) so dW/dt = -kW
5 0
3 years ago
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