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Alinara [238K]
3 years ago
7

Elizabeth noticed an increase of Mountain Bluebird sightings in her neighborhood. She wanted to know if there was an increase in

the population of the birds or if she was just noticing them more often because of recently learning their name while researching different species of birds. Match the processes Elizabeth used to answer her question to the step of the scientific method that it corresponds to.\
Physics
1 answer:
Nataly_w [17]3 years ago
8 0

Answer:

Male Mountain Bluebirds are entirely bright blue above and duller blue-gray below, but this bird has hints of chestnut coloration on his underparts, reminiscent of Eastern and Western Bluebirds. His appearance matches descriptions of hybrids between Mountain Bluebirds and Eastern or Western Bluebirds. These mixed pairs have been recorded multiple times. Their offspring are also usually fertile, evidenced by successful nestings of hybrid adults with pure individuals.

Historical reports of mixed pairs have been most common between Mountain and Eastern Bluebirds, which are more closely related to each other than either is to Western Bluebirds. Many of these reports have come from where the ranges of Mountain and Eastern Bluebirds overlap — in the southern prairie provinces of Canada and the northern Great Plains states of the U.S. However, mixed pairs have been recorded in Nebraska, eastern Minnesota, and even southern Ontario, aided by the wanderlust of Mountain Bluebirds.

Explanation:

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Tems11 [23]
Ultraviolet light with a wavelength shorter than visible light and a higher radiant energy than visible light.

The shorter the wavelength, the higher the frequency and energy.
6 0
3 years ago
Read 2 more answers
While tuning a string to the note C at 523 Hz, a piano tuner hears 2.00 beats/s between a reference oscillator and the string.
lara31 [8.8K]

Answer:

a)the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b) 526hz

c)0.989 or a 1.14% decrease in tension

Explanation:

a) While tuning a string at 523 Hz,piano tuner hears 2.00 beats/s between a reference oscillator and the string.

The possible frequencies of the string can be calculated by

fl=f' - B

where

fl= lower limit of the possible frequency

f'= frequency of the string

B= beat heard by the tuner

fl= 523hz + Or - (2beats/secs * 1hz/1beat per sc)

fl= 521hz or 525hz

So the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b)fl=f' - B

523hz= f' - 3

f'= 523 + 3= 526hz

c) The tension is directly proportional to the square of the frequencies

T1/T2 =f1^2/f2^2

523^2 / 526^2 = 0.989 or a 1.14% decrease in tensio

6 0
3 years ago
The collision between a hammer and a nail can be considered to be approximately elastic. estimate the kinetic energy acquired by
Setler [38]

Here we can use momentum conservation as in this type of collision there is no external force on it

m_1v_{1i} + m_2v_{2i} = m_1 v_{1f} + m_2v_{2f}

now here we can say

m_1 = 10 g

v_{1i} = 0

m_2 = 550 g

v_{2i} = 3.5 m/s

now here we can say

10*0 + 550 * 3.5 = 10 v_{1f} + 550 v_{2f}

192.5 = v_{1f} + 55 v_{2f}

now by coefficient of restitution

for elastic collision we know that e = 1

v_{2f} - v_{1f} = e(v_{1i} - v_{2i})

v_{2f} - v_{1f} = 0 - 3.5

now by solving the two equation

56v_{2f} = 189

v_{2f} = 3.375 m/s

also we know that

v_{1f} = v_{2f} + 3.5 = 3.375 + 3.5 = 6.875 m/s

so final speed of the nail is 6.875 m/s


6 0
2 years ago
Read 2 more answers
Please help me with these two questions
Andre45 [30]

Answer:

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Explanation:

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4 0
3 years ago
Which of the following examples could this free body diagram describe? (Check all that apply)
boyakko [2]

Answer:

A car accelerating to the right

Explanation:

The free-body diagram shows all the forces acting on an object. The length of each arrow is proportional to the magnitude of the force represented by that arrow.

In this free-body diagram, we see that there are 4 forces acting on the object, in 4 different directions. We also see that the two vertical forces are equal so they are balanced, while the force to the rigth is larger than the force to the left: this means that there is a net force to the right, so the object is accelerating to the right.

Therefore, the correct answer is:

A car accelerating to the right

5 0
3 years ago
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