Employees execute tasks while entrepreneurs plan. An employee can take work day by day, whereas an entrepreneur has to consider how well the tasks are being performed relative to the long-term plan for the business.
Answer:
the final velocity of the two blocks is
the distance that A slides relative to B is
Explanation:
From the diagram below;
acceleration of A relative to B is : 
where
v = u + at

Making t the subject of the formula; we have:


which implies the distance that A slides relative to B.
The final velocities of the two blocks can be determined as follows:
v = u + at

Thus, the final velocity of the two blocks is
Answer:
4.5 s, 324 ft
Explanation:
The object is projected upward with an initial velocity of

The equation that describes its height at time t is
(1)
where t, the time, is measured in seconds.
In order to find the time it takes for the object to reach the maximum height, we must find an expression for its velocity at time t, which can be found by calculating the derivative of the position, s(t):
(2)
At the maximum heigth, the vertical velocity is zero:
v(t) = 0
Substituting into the equation above, we find the corresponding time at which the object reaches the maximum height:

And by substituting this value into eq.(1), we also find the maximum height:

Answer:
Wavelength of radio is wave is 3 m
Explanation:
Wavelength of radio is wave is

where

wavelength is

Answer:
c.) 25 N
Explanation:
We find the volume of the brick, knowing that the volume of a cube is given by the formula:

being l the side of the cube, which in this case is 10 cm or 0,1 m. Now we find the mass of the object, knowing the density and the Volume of the cube:

We find the weight by multiplying the mass of the object with the gravity constant.
