Calculate ΔS∘rxn for the following reaction. The ΔS∘ for each species is shown below the reaction.

The standard reduction potentials for the Ag+|Ag(s) and Zn2+| Zn(s) half-cell reactions are +0.799 V and -0.762 V, respectively.

mihalych1998 [28]

Answer: The potential of the given cell is 1.551 V

Explanation:

The given chemical cell follows:

$Zn(s)|Zn^{2+}(0.125M)||Ag^{+}(0.240M)|Ag(s)$

Oxidation half reaction: $Zn(s)\rightarrow Zn^{2+}(0.125M)+2e^-;E^o_{Zn^{2+}/Zn}=-0.762V$

Reduction half reaction: $Ag^{+}(0.240M)+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.799V$ ( × 2)

Net cell reaction: $Zn(s)+2Ag^{+}(0.240M)\rightarrow Zn^{2+}(0.125M)+2Ag(s)$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=0.799-(-0.762)=1.561V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Zn^{2+}]}{[Ag^{+}]^2}$

where,

$E_{cell}$ = electrode potential of the cell = ? V

$E^o_{cell}$ = standard electrode potential of the cell = +1.561 V

n = number of electrons exchanged = 2

$[Zn^{2+}]=0.125M$

$[Ag^{+}]=0.240M$

Putting values in above equation, we get:

$E_{cell}=1.561-\frac{0.059}{2}\times \log(\frac{(0.125)}{(0.240)^2})$

$E_{cell}=1.551V$

Hence, the potential of the given cell is 1.551 V

6 0

3 years ago

why is nitrous oxide sedation especially useful for control of soft tissue discomfort during dental hygiene procedure

Stolb23 [73]

Answer:

Because it has a quickly sedative effect and it has antimicrobial effect.

Explanation:

This gas is useful because is used to trait pain, reduce anxiety and promote relaxation, slow down the body reaction, so the dentist can use it to calm down the patients.

If the patient present some injuries, this gas can help in wound healing.

7 0

3 years ago

Milk of magnesia has the chemical formula Mg(OH)2. What is the mass of 3.2 moles of milk of magnesia? The molar Mass of magnesiu

GenaCL600 [577]

To calculate the mass of milk of magnesia given, we need certain data like molar mass of the compound which needs the atomic mass of the atoms in the compound. We calculate as follows:

Molar mass of Mg(OH)2 = 24.3 g/mol + (2 x (16 + 1.0)) = 58.30 g/mol

Mass = 3.2 mol (58.30 g/mol) = 186.56 grams

3 0

3 years ago

Which of the following atoms would be expected to be diamagnetic in the ground state?

Rufina [12.5K]

The atoms that would be expected to be diamagnetic in the ground state is magnesium

The magnetism of an atom refers to its electronic configuration. A diamagnetic atom is an atom whose electrons are all paired.

A paired electron is an electron that occurs in pairs in its orbital shell.

At their respective ground state, the electronic configuration of the given elements are as follows:

The electronic configuration of magnesium is 1s²2s²2p⁶3s². As such its a diamagnetic atom.

The electronic configuration of Potassium is 1s²2s²2p⁶3s²3p⁶4s¹. Hence, Potassium has one unpaired electron in its outermost shell.

The electronic configuration of Chlorine is 1s²2s²2p⁶3s²3p⁵. Hence, Chlorine has one unpaired electron in its outermost shell.

The electronic configuration of Cobalt is 1s²2s²2p⁶3s²3p⁶3d⁷4s². Hence, the unpaired electrons of Cobalt in its outermost shell are three.

Therefore, the atoms that are diamagnetic in the ground state is magnesium.

Learn more about diamagnetic atoms here:

brainly.com/question/18865305?referrer=searchResults

8 0

2 years ago

Solid lithium (Li) reacts with water to produce hydrogen gas (H) and a solution of lithium

netineya [11]

Answer:

Li(s) + H20(l) --> LiOH(aq) + H(g)

Explanation:

it is already balanced

6 0

2 years ago