Answer:
1.265 Pounds
Explanation:
Data provided:
Tire outside diameter = 49"
Rim diameter = 22"
Tire width = 19"
Now,
1" = 0.0254 m
thus,
Tire outside radius, r₁ = 49"/2 = 24.5" = 24.5 × 0.0254 = 0.6223 m
Rim radius, r₂ = 22" / 2 = 11" = 0.2794 m
Tire width, d = 19" = 0.4826 m
Now,
Volume of the tire = π ( r₁² - r₂² ) × d
on substituting the values, we get
Volume of air in the tire = π ( 0.6223² - 0.2794² ) × 0.4826 = 0.46877 m³
Also,
Density of air = 1.225 kg/m³
thus,
weight of the air in the tire = Density of air × Volume air in the tire
or
weight of the air in the tire = 1.225 × 0.46877 = 0.5742 kg
also,
1 kg = 2.204 pounds
Hence,
0.5742 kg = 0.5742 × 2.204 = 1.265 Pounds
Their momentum is the same.
momentum of dolphin=50kg*16.4m/s=820kg*m/s
momentum of elephant=4100kg*0.20m/s=820kg*m/s
Assuming that you're given either an initial or final velocity, you can use the following equation and solve for the initial or final velocity.
Vyf² = Vyi² - 2g(y - y₀)
Where,
Vyf² = final velocity
Vyi₂² = initial velocity
g = 9.81 m/s²
(y - y₀) = the change in the distance along the y-axis.
You'll need also determine the positive and negative of your y-axis for your final solution because velocity can be positive or negative based on direction. Lastly, don't forget to square root both sides of your equation for your velocity.
I hope this helps.
Answer:
0.477 Hz
2.09 s
Explanation:
y = A sin(ωx − φ)
A is the amplitude, ω is the angular frequency, and φ is the phase shift.
ω = 3 rad/s
f = ω / 2π ≈ 0.477 Hz
T = 1/f ≈ 2.09 s
