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3 years ago

If the mole fraction of sulfuric acid H2SO4 is 0.432 what is the percent by mass of H2SO4.

Chemistry

1 answer:

Sever21 [200]3 years ago

4 0

Answer:

19.47%

Explanation:

The percentage by mass of $H_2SO_4$ would be 19.47%.

The percentage by mass of a substance in solution is calculated as:

$\frac{mass of substance}{mass of substance + water} * 100%$

Given that the mole fraction of $H_2SO_4$ = 0.432

The total number of mole fraction of a solution = 1

Hence, mole fraction of water = 1 - 0.432 = 0.568

Mass of water = molar mass x mole

= 98.079 x 0.432 = 42.37 g

Mass of $H_2SO_4$ = molar mass x mole

= 18.02 x 0.568 = 10.24 g

Hence,

%mass of $H_2SO_4$ = $\frac{10.24}{10.24 + 42.37} * 100$

= 19.47%

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