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Lilit [14]
3 years ago
11

If the mole fraction of sulfuric acid H2SO4 is 0.432 what is the percent by mass of H2SO4.

Chemistry
1 answer:
Sever21 [200]3 years ago
4 0

Answer:

19.47%

Explanation:

<em>The percentage by mass of </em>H_2SO_4<em> would be </em><em>19.47%</em><em>.</em>

The percentage by mass of a substance in solution is calculated as:

   \frac{mass of substance}{mass of substance + water}  * 100%

Given that the mole fraction of H_2SO_4 = 0.432

The total number of mole fraction of a solution = 1

Hence, mole fraction of water = 1 - 0.432 = 0.568

Mass of water = molar mass x mole

                              = 98.079 x 0.432 = 42.37 g

Mass of H_2SO_4 = molar mass x mole

                          = 18.02 x 0.568 = 10.24 g

Hence,

<em>%mass of</em> H_2SO_4 = \frac{10.24}{10.24 + 42.37} * 100

                         = 19.47%

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