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Semmy [17]
3 years ago
9

What is the difference between luxury and a necessity

Physics
1 answer:
myrzilka [38]3 years ago
7 0
Luxury is an antonym of necessity. Necessity is an antonym of luxury.
As nouns the difference between necessity and luxury is that necessity is the quality or state of being necessary, unavoidable, or absolutely requisite while luxury is very wealthy and comfortable surroundings.
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Consider a disk of radius 4.9 cm, having a uniformly distributed charge of +6.1 μC. The value of the Coulomb constant is 8.98755
gayaneshka [121]

Answer:

the electric field is 42.8×10^6 N/C

Explanation:

let k be the coulomb constant, Q be the charge distribution , R be the radius of the disk and x be the distance from the center.

k = 8.98755×10^9 N×m^2/c^2

Q = 6.1×10^-6 C

R = 4.9×10^-2 m

x = 3.1×10^-3 m

5 0
3 years ago
T.E = K.E + P.E
Rasek [7]

Answer:

T.E=K.E+P.E

:146,000J=81250J+K.E

4 0
2 years ago
How much energy is needed to melt 150 g of ice at 0°C to water? (1)(Lf =3.34˟ 10⁵ J/Kg)
NARA [144]

Answer:

5.01×10⁴ J.

Explanation:

Applying,

q = Cm....................... Equation 1

Where q = amount of heat needed to melt the ice, m = mass of the ice, C = specific latent heat of ice.

From the question,

Given: m = 150 g = (150/1000) kg = 0.15 kg, C = 3.34×10⁵ J/kg

Substitute these values into equation 1

q = (0.15×3.34×10⁵)

q = 0.501×10⁵ J

q = 5.01×10⁴ J.

5 0
3 years ago
A pencil rolls horizontally of a 1 meter high desk and lands .25 meters from the base of the desk. How fast was the pencil rolli
vovikov84 [41]

Answer: 0.55 m/s

Explanation:

This situation is related to projectile motion (also called parabolic motion), where the main equations are as follows:

x=V_{o} cos\theta t (1)

y=y_{o}+Vo sin \theta t + \frac{g}{2}t^{2} (2)

Where:

x=0.25 m is the horizontal displacement of the pencil

V_{o} is the pencil's initial velocity

\theta=0\° since we are told the pencil rolls <u>horizontally</u> before falling

t is the time since the pencil falls until it hits the ground

y_{o}=1 m  is the initial height of the pencil

y=0  is the final height of the pencil (when it finally hits the ground)

g=-9.8m/s^{2}  is the acceleration due gravity, always acting vertically downwards

Begining with (1):

x=V_{o} cos(0\°) t (3)

x=V_{o}t (4)

Finding t from (2):

0=1 m+ \frac{-9.8m/s^{2}}{2}t^{2} (5)

t=\sqrt{\frac{-2y_{o}}{g}} (6)

Substituting (6) in (4):

x=V_{o}\sqrt{\frac{-2y_{o}}{g}} (7)

Isolating V_{o}:

V_{o}=\frac{x}{\sqrt{\frac{-2y_{o}}{g}}} (8)

V_{o}=\frac{0.25 m}{\sqrt{\frac{-2(1 m)}{-9.8m/s^{2}}}} (9)

Finally:

V_{o}=0.55 m/s

4 0
3 years ago
describe the motion of objects that are viewed from your reference frame both inside and outside while you travel inside a movin
V125BC [204]

Answer:

The objects outside the reference frame aren't moving. It appears this way since the vehicle you are inside is moving, but unless the objects are people, animals, or other vehicles, the objects aren't moving.

3 0
2 years ago
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